<u>Ans 1:</u>
Ammonia is not collected over water since it is highly soluble in water
<u>Ans 2:</u>
Ammonia gas is lighter than air and hence collected by the downward displacement of air.
<u>Ans 3:</u>
The carbon dioxide is very cold as it comes out of the extinguisher, so it cools the fuel as well.
<u>Ans 4:</u>
H₂SO₄ is not used in the preparation of carbon dioxide Because the calcium sulphate formed is insoluble in water. So, CO₂ will not form.
<u>Ans 5:</u>
The opening of hard glass test tube is slanted down during laboratory preparation of ammonia gas because Ammonia gas is not collected in the gas jar by upward displacement of air because it is lighter than air
<u>Ans 6:</u>
Magnesium is reactive enough to be combusted and oxidized in a reaction with carbon dioxide:
The magnesium strip burns brightly in the air, but continues to burn in the carbon dioxide environment
<u>-</u><u>TheUnkownScientist</u>
The carbon dioxide in the headspace above the liquid is at higher pressure than atmospheric pressure outside the can.
The gas is at a lower volume initially but suddenly has a larger volume available when the can is opened.
The change in pressure as the gas rapidly moves to become dispersed through its new volume causes the "whoosh" sound.
The gas law that applies is Boyle's law.
This above is the exact answer for edgunity
Answer:

Explanation:
Hello,
In this case, since the given undergoing chemical reaction is correctly balanced, the reaction quotient is computed as well as the equilibrium constant but in terms of the given concentrations that are:

In such a way, the reaction quotient turns out:

Taking into account that carbon is not included since it is solid.
Best regards.
Two or more atoms<span> may </span>bond<span> with each other to form a molecule. When two hydrogens and an oxygen share electrons via covalent </span>bonds<span>, a water molecule is formed. Chemical reactions </span>occur<span> when two or more </span>atoms bond<span> together to form molecules or when bonded </span>atoms are broken<span> apart.</span>