(NH4)3PO4 :
N = 14 * 3 = 42
H = 1 * 12 = 12
P = 31 * 1 = 31
O = 16 * 4 = 64
-------------------------
42+12+31+64 = 149 g / mol
Hope this helps!.
Answer:
95,000 centigrams
Explanation:
There is 1000 CG in 0.01 kilograms
so you do 1000*95 which equals 95,000 centigrams.
Electrons is what defines which element appears in which block.
Answer: 3.7 x10−6 Mole per dm^3
Explanation:
pH is the negative logarithm of hydrogen ion concentration in a solution.
So, pH = - log(H+)
Since the solution has a pH of 5.43
5.43 = -log(H+)
To get hydrogen ion concentration, find the Antilog of 5.43
(H+) = Antilog (-5.43)
(H+) = 0.000003715
Then, 0.000003715 in standard form becomes 3.7 x10−6 M
Thus, the concentration of hydrogen ion in the solution is 3.7 x10−6 Mole per dm^3
Answer:
The answer to your question is 0.33 moles of H₃PO₄
Explanation:
Data
moles of Ca(OH)₂ = 0.050
moles of H₃PO₄ = ?
Process
1.- Write the balanced chemical equation
3Ca(OH)₂ + 2H₃PO₄ ⇒ Ca₃(PO₄)₂ + 6H₂O
Reactants Elements Products
3 Ca 3
12 H 12
14 O 14
2.- Calculate the moles of phosphoric acid
3 moles of calcium hydroxide --------------- 2 moles of phosphoric acid
0.5 moles of calcium hydroxide ----------- x
x = (0.5 x 2)/3
x = 0.33 moles