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Natalija [7]
2 years ago
15

636366 what is the area

Mathematics
1 answer:
mixas84 [53]2 years ago
8 0

Answer:

Thats not a full question

Step-by-step explanation:

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Determine the amplitude (A), period (P), and phase shift (PS) of the function f(x)= 3sin(x-4)+9
Tpy6a [65]
ANSWER

D.
A=3,P=2\pi,PS=(4,9)

EXPLANATION

The given function is

f(x) = 3 \sin(x - 4) + 9

Comparing to the general form of a trigonometric sine function,

f(x) = A \sin(Bx-C)+D

A=3
The amplitude is absolute value of A

|A| = |3| = 3

B=1

The period is given by

p = \frac{2\pi}{ B}

p = \frac{2\pi}{ 1} = 2\pi

C=4

is a shift to the right of 4 units.

and

D=9

is an upward shift of 9 units

Therefore the phase shift is (4,9).

The correct answer is D
6 0
3 years ago
Which equations have no solution? Check all that apply.
charle [14.2K]
Remember, |n|≥0 for all real numbers n

so

-|x|=0
times -1
|x|=0
true, x=0, has a solution

|x|=-15
false, can't have negative absolute value

-|x|=12
|x|=-12
false, no negative absolute value

-|-x|=9
|-x|=-9
false, no negative absolute value

-|-x|=-2
|-x|=2
x=2 or -2
true, has solutions



the ones that have no solutions are
|x|=-15
-|x|=12
-|-x|=9
5 0
3 years ago
Read 2 more answers
A 6-ft-tall person casts a shadow 5 ft long. A nearby tree casts a shadow 40 feet long. What is the height of the tree?
taurus [48]

Answer:

The tree is 48 feet tall.

Step-by-step explanation:

Cross multiply. ⇒ \frac{5}{6} x\frac{40}{x}

5 times 8 equals 40, so 6 times 8 equals ___?

Solve. ⇒  \frac{5}{6} x\frac{40}{x} =48

The tree is 48 feet tall.

8 0
3 years ago
Ethan correctly answers 80% of the total questions on his history test. He correctly answers 32 questions. How many total questi
dedylja [7]

Answer:

40 total questions

Step-by-step explanation:

4 0
3 years ago
A farmer has 1800 feet of fence and wants to enclose a rectangular field with two internal fences parallel to one side. What are
andrew-mc [135]
So.. if you notice the picture below.. .the length is that much

thus    \bf A=lw\qquad \cfrac{1800-3w}{2}=l\implies 900-\cfrac{3w}{2}=l
\\\\\\
A=\left( 900-\cfrac{3w}{2} \right)w\implies A=900w-\cfrac{3w^2}{2}\implies A=900w-\cfrac{3}{2}w^2

take the derivative of A, zero it out, and then check the critica points for any maxima by using the first-derivative test

8 0
3 years ago
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