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kobusy [5.1K]
3 years ago
14

M^2/n^2 is equivalent to ____

Mathematics
1 answer:
Mkey [24]3 years ago
5 0
M^2 × n^(-2) ........
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(25 POINTS) Find the coordinates of the missing endpoint if E is the midpoint of DF such that F(2,9) and
Natali5045456 [20]

Answer:

(-5, 3)

Step-by-step explanation:

The coordinates of the midpoint are the averages of the endpoints.

-1.5 = (x + 2) / 2

-3 = x + 2

x = -5

6 = (y + 9) / 2

12 = y + 9

y = 3

5 0
3 years ago
The square below has an area of x^2-10x+25 square meters
Helen [10]

Answer:

Answer: Expression that represents the length of one side of the square is x - 5.

5 0
3 years ago
Leonard and Marcus have saved up a total of $47.00. Leonard has saved 3 dollars less than 3/5 as much as Marcus. How much has Ma
shtirl [24]

Answer:

marcus saved 31.25

Step-by-step explanation:

8 0
3 years ago
If x = 7, what is the value of 3 times x²​
stira [4]

Answer:

147

Step-by-step explanation:

x = 7,

3x² = 3 × 7²

= 3 × 49

= 147

5 0
2 years ago
Verify the following identity and show steps<br><br> (Cos2 θ)/(1+sin2 θ)= (cot θ-1)/(cot θ+1)
Paul [167]

Answer:

Verified below

Step-by-step explanation:

We want to show that (Cos2θ)/(1 + sin2θ) = (cot θ - 1)/(cot θ + 1)

In trigonometric identities;

Cot θ = cos θ/sin θ

Thus;

(cot θ - 1)/(cot θ + 1) gives;

((cos θ/sin θ) - 1)/((cos θ/sin θ) + 1)

Simplifying numerator and denominator gives;

((cos θ - sin θ)/sin θ)/((cos θ + sin θ)/sin θ)

This reduces to;

>> (cos θ - sin θ)/(cos θ + sin θ)

Multiply top and bottom by ((cos θ + sin θ) to get;

>> (cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ)

In trigonometric identities, we know that;

cos 2θ = (cos² θ - sin²θ)

cos²θ + sin²θ = 1

sin 2θ = 2sinθcosθ

Thus;

(cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ) gives us:

>> cos 2θ/(1 + sin 2θ)

This is equal to the left hand side.

Thus, it is verified.

5 0
3 years ago
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