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murzikaleks [220]

3 years ago

12

HELP PLEASE I NEED IT ASAP I WILL MARK BRAINLIEST FOR CORRECT ANSWER

2 answers:

Liono4ka [1.6K]3 years ago

7 0

Answer:

wait whats "a" so confused

Step-by-step explanation:

Ymorist [56]3 years ago

5 0

6 that’s the answer

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WILL MARK BRAINLIEST

Simora [160]

Answer:

B. (-0.5, 5.75)

Step-by-step explanation:

I graphed the equation on the graph below to find the vertex of the equation.

8 0

4 years ago

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Twelve years from now, you will be inheriting $60,000 What is this inheritance worth to you today if you can earn 6.0 percent in

aivan3 [116]

Answer:

Twelve years from now, you will be inheriting $60,000 What is this inheritance worth to you today if you can earn 6.0 percent interest, compounded annually? Feedback: Present value = $60,000/(1 + . 06) = $29,818.16 18. You want to have $32,000 for a down payment on a house 5 years from now.

Step-by-step explanation:

brainliest plz also you are very beautiful :)

6 0

3 years ago

BRAINLIEST if right!<br><br> What is the solution of the system of inequalities

Vadim26 [7]

Answer:

Step-by-step explanation:

B

7 0

3 years ago

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

3 years ago

Which are the roots of the quadratic function f(q) = 92 – 125?

Mariulka [41]

Answer:

There are no solution/no roots for f(q) = 92 - 125

5 0

3 years ago