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3 years ago

How many balls are in a sack if there are 2 sacks and 4 balls

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

7 0

Answer:

Step-by-step explanation:

Didnt really get your question but this is what i got i think ;/

2 = sacks

4 = balls

4/2 = 2

1 = 2

2 = 2

1 sack has 2 balls

second sack has 2 balls

altogether we have 4 balls

prohojiy [21]3 years ago

4 0

Answer:

Step-by-step explanation:

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Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

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2 years ago

Joseph buys a bag of 60 pieces of taffy. In the bag, there are 12 cinnamon pieces, 18 raspberry pieces, 18 key lime pieces, and

Rus_ich [418]

You take the amount of raspberry pieces and divide with the total of taffy pieces

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2 years ago

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34kurt

Answer:

mean = 4

medin = violet

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Step-by-step explanation:

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2 years ago

Solve the equation. PLS

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A chemical refinery needs a vat. They want the vat to be a rectangular prism (with square bases) that has a maximum volume of 1,

Alex17521 [72]

Answer:

For least material to be used lengths of square base and sides = 10 units.

Step-by-step explanation:

Let the lengths of the square base and the sides = x feet, x feet and y feet

Area of the square base = x² feet

Volume of the rectangular prism = Area of the square base × Height

= x²y cubic feet

1000 = x²y

y = $\frac{1000}{x^2}$ -------(1)

Material used in the prism = Surface area of the rectangular prism

= 2(lb + bh + hl)

Here, h = height of the prism

l = length of the base

w = Width of the base

Material to be used (S) = 2(xy + x² + xy) - Area of lid

S = 2(x² + 2xy) - x²

S = x² + 2xy

Now by substituting the value of y from equation (1),

S = x² + $2x(\frac{1000}{x^{2} })$

= x² + $\frac{2000}{x}$

For least amount of material used,

We will find the derivative of the given function and equate it to zero.

S' = 2x - $\frac{2000}{x^{2} }$

2x - $\frac{2000}{x^{2} }$ = 0

2x³ = 2000

x³ = 1000

x = 10 feet

From equation (1),

y = $\frac{1000}{(10)^2}$

y = 10 feet

Therefore, for least amount of the material used lengths of square base and sides will be 10 feet.

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2 years ago