Check the picture below.
as you can see, the graph of the volume function comes from below goes up up up, reaches a U-turn then goes down down, U-turns again then back up to infinity.
the maximum is reached at the close up you see in the picture on the right-side.
Why we don't use a higher value from the graph since it's going to infinity?
well, "x" is constrained by the lengths of the box, specifically by the length of the smaller side, namely 5 - 2x, so whatever "x" is, it can't never zero out the smaller side, and that'd happen when x = 2.5, how so? well 5 - 2(2.5) = 0, so "x" whatever value is may be, must be less than 2.5, but more than 0, and within those constraints the maximum you see in the picture is obtained.
Answer:
D
Step-by-step explanation:
The factor theorem states if (x - h) is a factor of a polynomial p(x) then
p(h) = 0
However, p(h) ≠ 0 then the value obtained is the remainder.
Thus
p(3) = - 2
When p(x) is divided by (x - 3) then the remainder is - 2
Answer:
The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13
Step-by-step explanation:
Let x be the cost of 1 adult ticket
Let y be the cost of 1 child ticket
Cost of 8 adult tickets = 8x
Cost of 9 child tickets = 9y
We are given that A local kids play sold 8 adult tickets and 9 child tickets for a total of $205
So, 8x+9y=205 ----- 1
Cost of 4 adult tickets = 4x
Cost of 3 child tickets = 3y
We are given that 4 adult tickets and 3 child tickets for a total of $83.
4x+3y=83 ----2
Plot 1 and 2 on graph
8x+9y=205 -- Red line
4x+3y=83 -- Blue line
Intersection point provides the solution
So, Intersection point =(11,13)
So, The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13
Answer:
2m
Step-by-step explanation:
GCF of 8 and 18 is 2 and m is the only variable in both parts of the equation.
Answer:
(x + 3)(2x + 5)
Step-by-step explanation:
Given
2x² + 6x + 5x + 15 ← grouping the terms
= (2x² + 6x) + (5x + 15) ← factor each group
= 2x(x + 3) + 5(x + 3) ← factor out (x + 3) from each term
= (x + 3)(2x + 5) ← in factored form
