Answer:
YES
Step-by-step explanation:
Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.
Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.
Substitute ⁵/4 in y = kx
We would have:
y = ⁵/4x.
Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.
Let's plug in (16, 20) into y = ⁵/4x.
Thus substitute x = 16 and y = 20, we have:
[tex] 20 = \frac{5}{4}(16) [/trex]
[tex] 20 = (5)(4) [/trex]
[tex] 20 = 20 [/trex]
It makes the equation true. Therefore, the point, (16, 20) is a point on line l.
Answer:
Step-by-step explanation:
Recursive formula
tn = t_n-1 / 4
t2 = t1 / 4
t2 = 10240
t1 = 10240 / 4 = 2560
Explicit formula
tn = 10240 / 4^(n-1)
t4 = 10240 / 4^(4 - 1)
t4 = 10240 / 4^3
t4 = 10240 / 64
t4 = 160
t8 = 10240 / 4^7
t8 = 0,625
Answer:
c
Step-by-step explanation:
Answer:
the log function is the "inverse" function of an exponential function
by definition 
then 
in this problem you have 
thus what x solves this ? 
the answer is 
thus (100,2)
B) the x intercept is when y = 0
x intercept at (1,0)
C) at 100, the curve will hit y = 5000
Step-by-step explanation:
1) split the range in three identical invervals of size [6 - 0] / 3 = 2
2) form three rectangles
2a) First rectangle: base 2, height f(2) = 2^2 + 1 = 5
area 1 = base * height = 2 * 5 = 10
2b) second rectangle: base 2, height f(2+2) = 4^2 + 1 = 17
area 2 = 2 * 17 = 34
2c) third rectangle: base 2 height f(4+2) = 6^2 + 1 = 37
area 3 = 2*37 = 74
3) total area = area 1 + area 2 + area 3 = 10 + 34 + 74 = 118
