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3 years ago

How do you solve 0.3r = 2.1 I know the answer I just need to show my work

Mathematics

2 answers:

Afina-wow [57]3 years ago

8 0

0.3r=2.
r=2.1 divided by0.3
r=7

KatRina [158]3 years ago

5 0

Answer:

Step-by-step explanation:

0.3r = 2.1

r = 2.1 ÷ 0.3

r = 7

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In a sample of 700 gas stations, the mean price for regular gasoline at the pump was $2.894 per gallon and the standard deviati

frez [133]

Answer:

$P(x < 2.892) = 4.36\%$

Step-by-step explanation:

Given

$N = 700$ --- Population

$\mu = 2.894$ -- Mean

$\sigma = 0.009$ --- Standard deviation

$n = 55$ -- Sample

Required: $P(x < 2.892)$

This question will be solved using the finite correction factor

First, calculated the z score

$z = \frac{x - \mu}{\sqrt{\frac{N -n}{N -1}} * \frac{\sigma}{\sqrt n}}$

$z = \frac{2.892 - 2.894}{\sqrt{\frac{700 -55}{700 -1}} * \frac{0.009}{\sqrt {55}}}$

$z = \frac{-0.002}{\sqrt{\frac{645}{699}} * \frac{0.009}{7.42}}$

$z = \frac{-0.002}{\sqrt{0.92} * \frac{0.009}{7.42}}$

$z = \frac{-0.002}{0.95917 * 0.0012129}$

$z = -1.71$

So:

$P(x < 2.892) = P(z < -1.71)$

Using z table

$P(x < 2.892) = 0.043633$

$P(x < 2.892) = 4.36\%$

3 0

3 years ago

Find the zeros of the function.<br> f(x) = 2x2 – 2x – 12

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

2x^2-2x-12

This has solutions of x=3 and x= -2

3 0

3 years ago

Read 2 more answers

When solving a system of linear equations, try to algebraically form one equation that has only one variable.

lianna [129]

I believe the correct answer is true. <span>When solving a system of linear equations, try to algebraically form one equation that has only one variable. In this way, you can solve the value of that variable and eventually solve the other variables. Hope this answers the question. Have a nice day.</span>

3 0

3 years ago

Read 2 more answers

Someone please! Check the answer twice! I just want one wrong and that’s it please! NO FILES I SWEAR IF SOMEONE ADDS A FILE THEI

MakcuM [25]

Answer:

x = 55, because if you look the whole entire bar is 180° in total but you dont have to worry about that because that's not what the question is wanting you to look at, If you look really close there is a half and half on both sides so that means there is a 90° angle so you would have to take 90-35 and that is what gives you your missing angle which is 55.

5 0

2 years ago

The quadrilateral shown is rotated 90° clockwise about the origin. In which quadrant is the image of the quadrilateral located?

Viktor [21]

Answer:

Option (2). 1

Step-by-step explanation:

Coordinates of point A, B, C and D are,

A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).

Quadrilateral ABCD when rotated 90° clockwise about the origin,

Rule for the rotation of the vertices,

(x, y) → (y, -x)

Following the rule of rotation coordinates of the image points,

A(-4, 4) → A'(4, 4)

B(-2, 4) → B'(4, 2)

C(-2, 1) → C'(1, 2)

D(-4, 3) → D'(3, 4)

Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.

Option (2) is the correct option.

4 0

2 years ago