Question

Perimeter with radius 14

Answer 1

$360^o-150^o=210^o\\\\\dfrac{210^o}{360^o}=\dfrac{7}{12}$

$P_{LQM}=\dfrac{7}{12}\cdot2\pi\cdot14=\dfrac{7}{3}\pi\cdot7=\dfrac{49\pi}{3}\ cm$

$P_{QRP}=\dfrac{1}{2}\cdot14\pi=7\pi\ cm$

$P_F=\dfrac{49\pi}{3}+7\pi+3\cdot14\approx\dfrac{49}{3}\cdot\dfrac{22}{7}+7\cdot\dfrac{22}{7}+42=166\dfrac{2}{3}\ cm^2$