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evablogger [386]
3 years ago
12

Perimeter with radius 14

Mathematics
1 answer:
nevsk [136]3 years ago
6 0
360^o-150^o=210^o\\\\\dfrac{210^o}{360^o}=\dfrac{7}{12}

P_{LQM}=\dfrac{7}{12}\cdot2\pi\cdot14=\dfrac{7}{3}\pi\cdot7=\dfrac{49\pi}{3}\ cm

P_{QRP}=\dfrac{1}{2}\cdot14\pi=7\pi\ cm

P_F=\dfrac{49\pi}{3}+7\pi+3\cdot14\approx\dfrac{49}{3}\cdot\dfrac{22}{7}+7\cdot\dfrac{22}{7}+42=166\dfrac{2}{3}\ cm^2

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Answer:

Part 1

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Part 2

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Step 2 correction: P - 2·x = 2·y

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Step-by-step explanation:

Part 1

The student's steps are;

Step 1; P = 2·x + 2·y

Step 2: P + 2·x = 2·y

Step 3: P + 2·x/2 = y

The mistake in the work is in Step 2

The mistake is moving 2·x to the left hand side of the equation by adding 2·x to <em>P </em>to get; P + 2·x = 2·y

Part 2

To correct method to move 2·x to the left hand side of the equation, leaving only 2·y on the right hand side is to subtract 2·x from both sides of the equation as follows;

Step 2 correction: P - 2·x = 2·x + 2·y - 2·x = 2·x - 2·x + 2·y = 2·y

∴ P - 2·x = 2·y

(P - 2·x)/2 = y

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Required

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3 years ago
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Answer:

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