What you want is P(6∩1) or P(1∩6) or P(2∩5) or P(5∩2) or P(3∩4) or P(4∩3).
The events of rolling the dice are independent (i.e. they don't affect one another) so:
E.g.
P(6∩1) = P(6) * P(1)
P(2∩5) = P(2) * P(5)
The probability of getting a given number on a roll is 1/6 for both dice.
So:
P(6∩1) = 1/6 * 1/6 = 1/36
This is the same for any arrangement of numbers you could get from rolling two dice.
So, we can see that there are 6 arrangements of numbers that will give a sum of 7 and so that is 6 * 1/36 = 6/36 = 1/6
Answer:
A) 1/3200000
B) 19/20
Step-by-step explanation:
Percentage population of graduates = 5
Proportion of graduates from 100 random samples = percentage × number of samples
Proportion of graduates = 0.05 × 100 = 5
Probability of having 5 graduates among the 100 random samples:
P(1 graduate) = possible outcome / total required outcome
P(1 graduate) = (5 / 100) = 1/20
P(5 graduates) = (1/20)^5
P(5 graduates) = 1/3200000
Probability of never being a graduate = (1 - probability of being a graduate)
Probability of never being a graduate = ( 1 - (1/20)) = 19/20
Answer:
Introduction of yourself and an introduction to what your writing about
Answer:
x 
12
[12,∞]
Step-by-step explanation:
