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3 years ago

Question on the picture

Mathematics

2 answers:

Alecsey [184]3 years ago

6 0

It should be question D

anastassius [24]3 years ago

5 0

Answer:

$\mathtt{\huge\star{\pink{\underline{ option\: D }}}}\huge\star$

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Half of the product of b and c

icang [17]

"Product" signifies multiplication, and "half" means divide by two (or multiply by 1/2). So half the product of b and c is (bc)/2 or (1/2)(bc).

6 0

3 years ago

YES I KNOW IT IS NOT MATH BUT PLEASE HELP ME.

Goryan [66]

Answer:

Don't believe me but I think is at A

Step-by-step explanation:

4 0

3 years ago

The graph of function g is a vertical stretch of the graph of function f by a factor of 3. Which equation describes function g

anyanavicka [17]

Answer:

Step-by-step explanation:

A vertical stretch by a factor of k means that the point (x, y) on the graph of f (x) is transformed to the point (x, ky) on the graph of g(x), where k <1.

If k =1, then same graph we obtain and if k>1 we get a vertically shrink graph.

In our question, there is a vertical stretch of 3. This means new graph would have points as (x,y/3)

i.e. instead of f(x) = y, we have now f(x) = y/3

So transformation is g(x) = 3f(x)

Option A is correct.

2) Here f(x) = 3x+8 is transformed to g(x) =3x+6

i.e. y intercept is reduced by 2 units. Hence there is a translation of 2 units down.

8 0

3 years ago

Read 2 more answers

What is the total surface area of the

Tom [10]

Answer:

D:315

Step-by-step explanation:

6x7 and then divide by 2 = 21+21 =42 13x7= 91x3= 273+ 42= 315

6 0

3 years ago

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

3 years ago