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olganol [36]
3 years ago
8

Find the exact value of cos (u-v) given that sin u=-9/41 and cos v=15/17. (Both u and v are in quadrant IV)

Mathematics
1 answer:
siniylev [52]3 years ago
8 0
Please review the sum and difference formulas for the trig functions.

In this case you have the difference between two angles u and v and want to find the cosine of this difference.

Here's the appropriate formula:  

cos (a-b) = cos a cos b + sin a sin b

Given that sin u = -9/41, equal to the opp side over the hyp., we must find the length of the adj. side and then u itself.

opp side = - 9
hyp =           4
adj side = sqrt( 18+4) = sqrt(22)

Find the side opp angle v in a similar manner.

Then cos (u-v) = cos u cos v + sin u sin v becomes

                        = (cos u)(15/17) + (-9/41)(sin v)   (where you must find cos u and sin v)

See what you can do, then return and comment here if you need further help.  Good luck.

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a sequence starts a 200 and 30 is subtracted each time 200,170,140 what are the first two numbers in the sequence that are kess
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<h3>Answer:  -10 and -40</h3>

===============================================================

Explanation:

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Tn = nth term

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and lastly

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Or once you determine that T7 = 20, you subtract 30 from it to get 20-30 = -10 which is the value of T8. Then T9 = -40 because -10-30 = -40.

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