Answer:
<em>b. 0.6024</em>
Step-by-step explanation:
<u>Conditional Probability</u>
Suppose two events A and B are not independent, i.e. they can occur simultaneously. It means there is a space where the intersection of A and B is not empty:

If we already know event B has occurred, we can compute the probability that event A has also occurred with the conditional probability formula

Now analyze the situation presented in the question. Let's call F to the fair coin with 50%-50% probability to get heads-tails, and U to the unfair coin with 32%-68% to get heads-tails respectively.
Since the probability to pick either coin is one half each, we have

If we had picked the fair coin, the probability of getting heads is 0.5 also, so

If we had picked the unfair coin, the probability of getting heads is 0.32, so

Being A the event of choosing the fair coin, and B the event of getting heads, then



The closest answer is
b. 0.6024
Answer:
53 + 1 = 54
give me brainllest if this is right okay?
Required data table is attached below :
Answer:
D. The fewest students prefer black Model A1 calculators.
Step-by-step explanation:
From the data Given :
Larger proportion of students prefer White calculators(0.65) to black calculators (0.35)
Also, Fewer proportion of students like black model C3 (0.20) than white model A1 (0.40)
Also, the proportion of students who like model C3 calculators(0.30) are fewer than those who prefer the model A1 (0.45)
Therefore, the true inference which can be derived from the data is, the least preferred calculator is the Black model A1 calculator with a proportion of 0.05
The answer is C. When multiplying the smaller rectangle by 2 on both sides, you will get the bigger rectangle’s measurements
(c+3)-2c-(1-3c)=2
c+3-2c-1+3c=2
2c+2=2
2c=0
c=0