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Shtirlitz [24]
3 years ago
10

1.8,1.35,2.5, squat root of 5 in least to greatest

Mathematics
2 answers:
Ber [7]3 years ago
3 0

Answer: 1.35, 2.5, 1.8

Step-by-step explanation:

Tju [1.3M]3 years ago
3 0

Answer:

Step-by-step explanation:

1) 2.5^=97.6

2) 1.8^5= 18.8

3) 1.35^5=4.4

or

1) 2.50

2) 1.80

3) 1.35

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Write an equation in slope-intercept form of the line that passes through (-1, 4) and (0,2).<br> y =
telo118 [61]

Answer:

y =( -1/2 )x + 2

Step-by-step explanation:

first step is to determine the slope of the line ( which is the rise over the run) or symbolically slope is defined as m= ∆x / ∆y, so plugging those values we get...

m= ∆x / ∆y = (-1 - 0) / (4 - 2) = -1 / 2

so next is to find the zero( y-intercept) of the function by ....

y = mx + b

y = ( -1/2)x + b (since m is equal to -1/2)

2 = ( -1/2)0 + b

2= b

3 0
3 years ago
Suppose that for a certain experiment p​(b​)equals=0.5 and p​(avertical line upper bb​)equals=0.2. find p​(aintersect∩b​).
raketka [301]
P(a | b) = p(a ∩ b)/p(b) . . . . . a definition worth remembering
0.2 = p(a ∩ b)/0.5 . . . . . . . . fill in the given values
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5 0
3 years ago
3.3333 as a simplified fraction
Irina18 [472]

3 1/3 would be the answer

5 0
3 years ago
Read 2 more answers
What is the domain and range of points (-6,-6) (6,2)
dusya [7]

Answer:domain {-6,6} range {-6,2}

6 0
3 years ago
Can anyone help me?
goldfiish [28.3K]

Given:

A right angle triangle ABC, right angled at C.

To find:

The measure of θ.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Opposite}{Adjacent}

In triangle ABC,

\tan \theta=\dfrac{AC}{BC}

\tan \theta=\dfrac{2.7}{5}

\tan \theta=0.54

It can be written as

\theta=\tan^{-1}0.54

\theta\approx 28.369

Therefore, the measure of θ is 28.369.

5 0
3 years ago
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