Help with what? I am not sure what other question you asked that you need help on. What is the question?
,..........................
Answer:
quadratic
y=mx+c
Step-by-step explanation:
Answer:
x = 5 and value of y = 2
Step-by-step explanation:
using substitution method
let;
x + 4y = 13...................... equation 1
x - y = 3............................... equation 2
from equation 2
x - y = 3.................................... eqn 2
x = y + 3.......................................... equation 3
put x = y + 3 in equation 1
x + 4y = 13...................... equation 1
y + 3 + 4y = 13
5y = 13 - 3
5y = 10
divide both sides by 5
i.e
5y/5 = 10/5
y = 2
sustitue for y = 2 in equation 3
x = y + 3.......................................... equation 3
x = 2 + 3
x = 5
therefore the value of x = 5 and value of y = 2
to check if your answwer is correct slot in the value of x and y in any of the equation . e.g
from equation 3
x = y + 3.......................................... equation 3
5= 2 + 3
5 =5....................... proved
Answer:
E, 297.1
Step-by-step explanation:
First, find the area of the triangle using the formula a= (bh) / 2
Base x height would be 16 x 12, which is 192
192 / 2 is 96 sq meters
Then, find the area of the circle using the formula a= Pi (r^2)
If the diameter is 16, the radius would be 8 because you divide by 2
8^2 is 64, 64 times Pi is approximately 201.1
Finally, add the areas together, 96 + 201.1 is 297.1 or E