Trying to solve a polynomial with brackets Problem: 5b-3[2(3-b)-5(3b-5]
1 answer:
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Answer: The equation of the circle as specified is (x+5)² + (y -1)² = 25
Step-by-step explanation: Use the Pythagorean Theorem to calculate the length of the radius from the coordinates given for the triangle location: A(-1,4), B(-1,1) and C(-5,1)
subtract y-values of A & B 4-1=3 AB = 3
subtract x-values of B &C -5-(-1) =4 BC=4 3² + 4² = 9 + 16 = 25
√25 = 5 AC = 5 That is the radiuus of the circle.
The sides of the triangle are AB=3, BC=4, AC=5.
Use the equation for a circle:
( x - h )² + ( y - k )² = r², where ( h, k ) is the center and r is the radius.
Use the coordinates of C, (-5, 1) as h and k in the equation
Substituting those values, we have (x -[-5])² + (y -[1])² = 5²
Simplify: (x+5)² + (y -1)² = 25
A graph of the circle is attached. The radius is AC, between the center C (-5,1) and A( -1,4) on the circumference. (Sorry, I still need to learn how to create line segments!)
