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3 years ago

Solve the inequality

Mathematics

1 answer:

trapecia [35]3 years ago

6 0

Answer:

x>-1

Step-by-step explanation:

Subtract 0.7 from both sides

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Indicate true or false as to weather the following equation is quadratic x(x^2+1)=0 true or false

beks73 [17]

$\bf x(x^2+1)=0\implies \stackrel{distributing}{x^3+x=0}\impliedby \textit{notice the }^3\textit{, is not quadratic, is \underline{cubic}}$

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3 years ago

In this triangle, the product of sin B and tan C is<br> and the product of sin Cand tan B is

Ipatiy [6.2K]

Answer:

$\frac{c}{a}$ and $\frac{b}{a}$

Step-by-step explanation:

sinB = $\frac{opposite}{hypotenuse}$ = $\frac{AC}{BC}$ = $\frac{b}{a}$

tanC = $\frac{opposite}{adjacent}$ = $\frac{AB}{AC}$ = $\frac{c}{b}$

Thus

sinB tanC = $\frac{b}{a}$ × $\frac{c}{b}$ ( cancel b on numerator/ denominator )

= $\frac{c}{a}$

---------------------------------------------------------------------------

sinC = $\frac{opposite}{hypotenuse}$ = $\frac{AB}{BC}$ = $\frac{c}{a}$

tanB = $\frac{opposite}{adjacent}$ = $\frac{AC}{AB}$ = $\frac{b}{c}$

Thus

sinC tanB = $\frac{c}{a}$ × $\frac{b}{c}$ ( cancel c on numerator/ denominator )

= $\frac{b}{a}$

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2 years ago

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Afina-wow [57]

Answer:

Step-by-step explanation:

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Molodets [167]

$\bf \textit{circumference of a circle}\\\\
C=2\pi r\qquad 
\begin{cases}
r=radius\\
-----\\
r=5x^2
\end{cases}\implies C=2\pi 5x^2\implies C=10\pi x^2
\\\\\\
\textit{area of a circle}\\\\
A=\pi r^2\qquad 
\begin{cases}
r=radius\\
-----\\
r=5x^2
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3 years ago

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viva [34]

Answer:

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Step-by-step explanation:

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