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Jet001 [13]
3 years ago
15

Idk what end behavior for this?

Mathematics
2 answers:
Ad libitum [116K]3 years ago
4 0

Answer:

b

Step-by-step explanation:

The end behaviour is what happens when x gets larger and positive ( right hand end ) or larger and negative ( left hand end ) Tis is called the end behaviour as x → + ∞ and x → - ∞ respectively

For a polynomial the end behaviour is determined by the term of greatest degree.

For the given function

f(x) = x^{5} - 3x³ + 2x + 4 ← degree 5 polynomial

The leading coefficient is positive

• Odd degree, positive leading coefficient, then

as x → - ∞, f(x) → - ∞

as x → + ∞, f(x) → + ∞

----------------------------------------------------------------------

• Odd degree, negative leading coefficient, then

as x → - ∞, f(x) → f(x) → + ∞

as x → + ∞, f(x) → - ∞

dangina [55]3 years ago
3 0

Answer:

It is b.

Step-by-step explanation:

When x is negative x^5 will also be negative.

f(x) = x^5 - 3x^3 + 2x + 4

As x  --> -∞ x^5 will  be the main factor for f(x) --->  -∞ .

Similarly  x^5 will have the greatest influence when x ---> ∞, so f(x) ---> ∞.

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Horizontal shift of 1 unit to the left and a vertical shift downward of 2 units.

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2 years ago
Complete the table below for the equation y=2x+1 then graph the equation
AnnZ [28]

Answer:

I cant graph it but here’s how to solve for x

Step-by-step explanation:

Y=2x+1

    -1  -1

—————

y=1x+ 0

y=x or y=1x

7 0
3 years ago
Are all of the answers written in pencil correct?
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5 0
3 years ago
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kupik [55]
The temperature at 6:00 a.m. was –12°F. By 3:00 p.m. the temperature had risen 21F<span>°</span>.<span>What was the temperature at 3:00 p.m.?
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7 0
4 years ago
Certain transportation company has a fleet of 210 vehicles. The average age of the vehicles is 4.25 years, with a standard devia
-BARSIC- [3]

Answer:

z = \frac{4-4.25}{\frac{1.5}{\sqrt{40}}}= -1.054

And we can find the following probability:

P(z

And the last probability can be founded using  the normal standard distribution or excel.

Step-by-step explanation:

For this case we define the random variable X as the ages of vehicles. We know the following info for this variable:

\bar X = 4.25 represent the mean

\sigma =18/12=1.5 represent the deviation in years

They select a sample size of n=40>30. And they want to find this probability:

P(\bar X

Since the sample size is large enough we can use the central limit theorem and the distribution for the sample mean would be:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 4 we got:

z = \frac{4-4.25}{\frac{1.5}{\sqrt{40}}}= -1.054

And we can find the following probability:

P(z

And the last probability can be founded using  the normal standard distribution or excel.

3 0
3 years ago
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