Question

HELP ME!! I'LL GIVE BRAINLIEST!!

Answer 1

Answer:

$r(θ)= \frac{1}{32} {v}^{2} sin2θ$

Step-by-step explanation:

$r(θ)= \frac{1}{16 }v^2 sinθ cosθ. \\ \\ r(θ)= \frac{1}{16 } v^2 \times \frac{2sinθ cosθ}{2} . \\ \\ r(θ)= \frac{1}{16} {v}^{2} \times \frac{1}{2} \times sin2θ \\ \\ r(θ)= \frac{1}{16} \times \frac{1}{2} {v}^{2} sin2θ \\ \\ r(θ)= \frac{1}{32} {v}^{2} sin2θ$