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4 years ago

YOU WENT TO THE GYM LAST WEEK AND SPENT THE FOLLOWING AMOUNT OF YOUR TIME ON THE RUNNING MACHINE.

Mathematics

2 answers:

tia_tia [17]4 years ago

3 0

Thursday sonnnnnnnnnnnnn

ivann1987 [24]4 years ago

3 0

Answer: On Friday, he spend the least amount of time on the running machine.

Step-by-step explanation:

Since we have given that

Monday 0.3 = $0.3\times 100\%=30\%$

Tuesday = 15%

Wednesday = $\dfrac{1}{6}\times 100\%=16.67\%$

Thursday = $0.2\times 100\%=20\%$

Friday = $\dfrac{1}{8}\times 100\%=12.5\%$

Hence, we can compare all the days, and we get that

On Friday, he spend the least amount of time on the running machine.

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Belle bought 18 seeds in order to plant an herb garden for her grandma. Of the seeds she bought, 10 were parsley seeds.

Harrizon [31]

Answer:

0.3431

Step-by-step explanation:

Here, it can work well to consider the seeds from the group of 18 that are NOT selected to be part of the group of 15 that are planted.

There are 18C3 = 816 ways to choose 3 seeds from 18 NOT to plant.

We are interested in the number of ways exactly one of the 10 parsley seeds can be chosen NOT to plant. For each of the 10C1 = 10 ways we can ignore exactly 1 parsley seed, there are also 8C2 = 28 ways to ignore two non-parsley seeds from the 8 that are non-parsley seeds.

That is, there are 10×28 = 280 ways to choose to ignore 1 parsley seed and 2 non-parsley seeds.

So, the probability of interest is 280/816 ≈ 0.3431.

___

The notation nCk is used to represent the expression n!/(k!(n-k)!), the number of ways k objects can be chosen from a group of n. It can be pronounced "n choose k".

6 0

3 years ago

Problem #3

AfilCa [17]

Answer:

b = 115.4 feet

Step-by-step explanation:

b^2 = a^2 + c^2 - 2 (a)(b) x cos B

b^2 = 230^2 + 360^2 - 2(230)(360) x cos(38 degrees)

b^2 = 52,900 + 129,600 - 2(230)(360) x cos(38 degrees)

b^2 = 182,500 - 165,600 x cos(38 degrees)

b = $\sqrt{(16,900)(cos(38)) }$

b = 115.4 feet

i hope this helps!! :)

8 0

3 years ago

For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?

STatiana [176]

Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

$z=\frac{x-\mu}{\sigma}$