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2 years ago

13

The price of a computer was decreased by 7% to £500. What was the price before the decrease? Give your answer to the nearest pen

ny.

1 answer:

inessss [21]2 years ago

3 0

It’s 500.07
all i did was solve x-7%=500 and got 500.07.

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Elle can buy 2 quarts of milk for $3 or 1 gallon of milk for $3, Which Is The Better Deal.... Because Im not sure..

GrogVix [38]

1 gallon is equal to 4 quarts.

So you can either get 2 quarts for $3, or 4 quarts for 3$

1 gallon is the better deal.

5 0

3 years ago

Read 2 more answers

Suppose that the function g is defined, for all real numbers, as follows.

svetoff [14.1K]

Answer:

<em>a) g(-2) = 0</em>

<em>b) g(-1) =1</em>

<em>c) g(4) = 2</em>

Step-by-step explanation:

Given data

$g(x) = \frac{-1}{4x+1} if x < -2$

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

$g(x) = 2 if x >2$

<u><em>Step( i )</em></u>:-

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

put x = -2

$g(-2) = -(-2+1)^{2} +1 = -(-1)^{2}+1 = -1+1 =0$

<em>g(-2) = 0</em>

<u><em>Step(ii)</em></u>:-

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

Put x = -1

$g(-1) = -(-1+1)^{2} +1 = -(0)^{2}+1 = -0+1 =1$

<em>g(-1) =1</em>

<u><em>Step(iii)</em></u>:-

$g(x) = 2 if x >2$

<em>g(4) = 2</em>

<em></em>

7 0

2 years ago

What is 1/10 of 1000 what is 1% out of 100

Ulleksa [173]

To get 1/10 -> 1000/10 =100
and 1% of 100 -> 100/100 = 1 or 1%

100 for question 1
1 for q2

3 0

2 years ago

To what does the two-source rule refer?

Alla [95]

Step-by-step explanation:

p(A)={Ø,{2}{3},{2,3}

7 0

2 years ago

13.......................

Alla [95]

Answer:

The answer is (d) ⇒ $pq^{2}r\sqrt[3]{pr^{2}}$

Step-by-step explanation:

* To simplify the cube roots:

If its number then the number must be written in the form x³

then we divide the power by 3 to cancel the radical

If its variable we divide its power by 3 to cancel the radical

∵ $\sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}$

∴ $p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}$

∵ $p^{\frac{1}{3}}=\sqrt[3]{p}$

∵ $r^{\frac{2}{3}}=\sqrt[3]{r^{2}}$

∴ $p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})$

∴ $prq^{2}\sqrt[3]{pr^{2}}}$

∴ The answer is (d)

5 0

2 years ago