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Korolek [52]
3 years ago
8

I need help with this math question on my study guide!

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0
Sadly is right.  You must have practiced this stuff in middle school
until it was coming out of your ears.  Fortunately, you have a chance
to relearn it now.  You should do that ... it'll be important in any math
course you ever take.

'm' is the slope of the line on the graph.

The slope is

                (the change in 'y' between any two points on the line)
divided by
               (the change in 'x' between the same two points).

You can choose any two points on the line, and the slope is always the same.

To make it easy, look at the two points on this graph where the line crosses
the x-axis and the y-axis.

Going between these two points ...
-- the line goes up, from  y=0  to  y=4.  The change in 'y' is  4 .
-- the line goes to the right, from  x=-2  to  x=0.  The change in 'x' is  2 .

           'm' = the slope  =  (4)/(2)  =  2 .

The  "y-intercept"  is the place where the line crosses the y-axis.
On this graph, that's the point where  y=4 .

The equation of EVERY straight line on ANY graph is:

                 Y  =  (the slope) times 'x'  +  (the y-intercept) .

So the equation of THIS line on THIS graph is

                 Y = 2x + 4 .
 
You might be interested in
5/4q = 1/3 -2/3 + 2 help please
KengaRu [80]

Answer:

q=4/3

Step-by-step explanation:

simplify the right side, to 5/3

5/4q=5/3

multiply 4/5 on both sides

q = 5/3*4/5

q = 4/3

4 0
2 years ago
A landscaper needs 348 pounds of plant food. He has 114 pounds in his truck, and another 46 pound at his shop.
andrew-mc [135]

Answer:

\frac{19}{12}\ pounds

or

1\frac{7}{12}\ pounds

Step-by-step explanation:

<u><em>The correct question is </em></u>

A landscaper needs 3 4/8 pounds of plant food. He has 1 1/4 pounds in his truck, and another 4/6 pound at his shop. How many more pounds of plant food does the landscaper need?

Let

x ----> the additional pounds of plant food needed for the landscaper

we know that

The additional pounds of plant food needed for the landscaper plus the pounds in his truck plus the pounds in his shop must be equal to the total pounds of plant food needed

so

The linear equation that represent this problem is

x+1\frac{1}{4}+\frac{4}{6}=3\frac{4}{8}

Convert mixed number to an improper fractions

1\frac{1}{4}=1+\frac{1}{4}=\frac{4*1+1}{4}=\frac{5}{4}

3\frac{4}{8}=3+\frac{4}{8}=\frac{3*8+4}{8}=\frac{28}{8}=\frac{14}{4}

Substitute in the expression above

x+\frac{5}{4}+\frac{4}{6}=\frac{14}{4}

solve for x

Multiply by (4*6) both sides to remove the fractions

24x+30+16=84

Combine like terms left side

24x+46=84

subtract 46 both sides

24x=84-46

24x=38

Divide by 24 both sides

x=\frac{38}{24}\ pounds

simplify

x=\frac{19}{12}\ pounds

Convert to mixed number

\frac{19}{12}\ pounds=\frac{12}{12}+\frac{7}{12}=1\frac{7}{12}\ pounds

7 0
4 years ago
The leg of a right triangle is 5 units and the hypotenuse is 8 units. What is the length, in units, of the other leg of the tria
12345 [234]
I hope this helps you

4 0
3 years ago
It has been suggested that night shift-workers show more variability in their output levels than day workers (σ2N &gt; σ2D). Bel
Murljashka [212]

Answer:

<em>Calculated |t |= 7.72 > 2.1314 at 0.05 level of significance </em>

<em>Null hypothesis is rejected </em>

<em> The night shift-workers show more variability in their output levels are greater than day workers </em>

Step-by-step explanation:

<u>Step(i):</u>-

Given first sample size n₁ = 9

Given mean of the first sample x₁⁻ = 520

Given sample variance of the first sample'S²₁' = = 38

Standard deviation of the first sample 'S₁' = √38 =6.16

Given second sample size n₂ = 8

Given mean of the second sample x₂⁻ = 540

Given sample variance of the second sample ( 'S²₂' = 20

Standard deviation of the second sample 'S₂' = √20 = 4.4712

<u><em>Step(ii):-</em></u>

<em>Null hypothesis :H₀:  σ²₁ =σ²₂</em>

<em>Alternative Hypothesis:H₁: σ²₁ > σ²₂</em>

<em>Test statistic </em>

<em>               </em>t = \frac{x^{-} _{1} - x^{-} _{2} }{\sqrt{\frac{S^2_{1} }{n_{1} }+\frac{S^2_{2} }{n_{2} }  } }<em></em>

<em>              </em>

            t = \frac{520 - 540 }{\sqrt{\frac{38 }{9 }+\frac{20 }{8 }  } }

           t =    - 7.72

          |t| = |- 7.72| = 7.72

Degrees of freedom

<em> ν = n₁ + n₂ -2 = 9 +8 -2 = 15</em>

<em>t₀.₀₅ = 2.1314</em>

<u><em>Final answer</em></u><em>:-</em>

<em>Calculated |t |= 7.72 > 2.1314 at 0.05 level of significance </em>

<em>Null hypothesis is rejected </em>

<em> The night shift-workers show more variability in their output levels are greater than day workers </em>

4 0
3 years ago
What is the sum of the first 20 terms of the series below?
Natalija [7]

Answer:

Step-by-step explanation:

Now to find the sum of first 20 terms, substitute n=20,a=−1 and d=4 in S n = 2n [2a+ (n−1)d] as follows: S 20 = 220 [(2×−1)+(20−1)4]=10[−2+(19×4)]=10(−2+76)=10×74=740 Hence, the sum of first 20 terms is 740.

6 0
3 years ago
Read 2 more answers
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