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3 years ago

Find the residual if you know the actual number is 3 and the predicted value is 1.6

Mathematics

1 answer:

IgorC [24]3 years ago

5 0

Answer:

The correct option is A.

Step-by-step explanation:

The difference between actual value and predicted value is called residual.

Formula of residual is

$e=y-\hat{y}$

Where, y is observed value or actual value and $\hat{y}$ is predicted value.

$e=3-1.6$

$e=1.4$

The value of residual is 1.4 and option A is correct.

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Apply the power of a power property to simplify y 4/3• y 2/3 - 1/2 = y2- - 1/2 =

prohojiy [21]

Answer:

$y^{ \frac{3}{2}}$

Step-by-step explanation:

From the question posted, you've already initiated the solution but you applied a wrong approach;

Given

$y^{\frac{4}{3}} . y^{\frac{2}{3} - \frac{1}{2}}$

Required

Simplify; using power property

Power property states that;

$a^m.a^n = a^{m+n}$

$a^m/a^n = a^{m-n}$

By comparison; we have to apply the first property;

This is shown below;

$y^{\frac{4}{3}+\frac{2}{3} - \frac{1}{2}}$

Add fraction of the same numerator

$y^{\frac{4+2}{3} - \frac{1}{2}}$

$y^{\frac{6}{3} - \frac{1}{2}}$

$y^{2 - \frac{1}{2}}$

Subtract fraction

$y^{ \frac{4-1}{2}}$

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The expression $y^{\frac{4}{3}} . y^{\frac{2}{3} - \frac{1}{2}}$ is equivalent to $y^{ \frac{3}{2}}$

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