Andrew is shooting arrows at a target.
1 answer:
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Answer:
The figure is attached down
Step-by-step explanation:
To graph a line you must have its equation
The form of the linear equation is y = m x + b, where
- m is its slope
- b is the y-intercept (y at x = 0)
∵ The slope of the line is
∴ y = x + b
- To find b substitute x and y in the equation by the coordinates
of a point on the line
∵ The line passing through point (-5 , -4)
∴ x = -5 and y = -4
∵ -4 = (-5) + b
∴ -4 = + b
- Subtract from both sides
∴ = b
∴ y = x -
To draw the line substitute x by any two values and find their ys
∵ x = -2
∴ y = (-2) -
∴ y = -6
∴ The line passing through point (-2 , -6)
∵ x = 1
∴ y = (1) -
∴ y = -8
∴ The line passing through point (1 , -8)
∵ x = 4
∴ y = (4) -
∴ y = -10
∴ The line passing through point (4 , -10)
Now we can make a table to draw the line
→ x : -5 : -2 : 1 : 4
→ y : -4 : -6 : -8 : -10
Plot the points on the graph paper and draw the line
<em>Look to the attached graph</em>
Answer:
∠AKB = 22°
Step-by-step explanation:
Call the point of intersection of BK and AC point P. Then line BK is a transversal to parallel lines AK and BC. Alternate interior angles AKB and PBC will be congruent.
We know that angle PCB is 68°, the difference between 180° and the sum of the two given angles in ΔABC:
∠PCB = 180° -∠PAB -∠ABC = 180° -59° -53° = 68°
Since PB is an altitude, ∠CPB is a right angle. Then ∠PBC is the complement of ∠PCB, so is ...
∠PBC = 90° -68° = 22°
As we said, this is congruent to ∠AKB, so ...
∠AKB = 22°
