Answer:
<h3>9 months</h3>
Step-by-step explanation:
Given the relationship of the dogs weight ang its age modeled by the equation;
w = 6m+4
m represents its age in months, and;
w represents its weight in pounds
Given
w = 58pounds
Required
number of months m before the dog weigh 58pounds;
Substitute w = 58 into the function and get m as shown;
w = 6m + 4
58 = 6m + 4
subtract 4 from both sides
58-4 = 6m+4-4
54 = 6m
divide both sides by 6
54/6 = 6m/6
9 = m
m = 9
Hence it will take 9months before the dog will weigh 58 pounds
Answer:
26hr
Step-by-step explanation:
12 calls/hr
480 calls/wk
If Juanita has made 168 calls this week, it meants she still has to make 312 calls. So, 312 calls ÷ 12calls/hr = 26hr
Juanita needs to work 26hr mores to reach the weekly goal.
Answer:
-2
Step-by-step explanation:
You plug the values in. 2(2)-3=1, and 2(3)-3=3
1-3=-2
Hope I helped!
8^2 is 64 and 2^2 is 4. When you add them together you get 68.
(8+2)^2 is the same as 10^2 which is 100.
68≠100
You can write the two equations x = 4y - 7 and x + y = 93; substitute the value of x into the other equation
(4y - 7) + y = 93; combine like terms
5y - 7 = 93; add 7 to both sides
5y = 100; divide both sides by 5
y = 20; substitute this value into the other equation
x + 20 = 93
x = 73
So the numbers are 20 and 73