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2 years ago

Write the term in simplest form and then simplify the expression

Mathematics

1 answer:

taurus [48]2 years ago

4 0

Answer: $\bold{-19\sqrt{6}+8\sqrt{5}}$

<u>Step-by-step explanation:</u>

$.\quad 3\sqrt{24}-7\sqrt{54}-\sqrt{96}+4\sqrt{20}\\\\=3\sqrt{\underline{2\cdot 2}\cdot2 \cdot3}-7\sqrt{2\cdot 3\cdot\underline{3\cdot 3}}-\sqrt{\underline{2\cdot 2}\cdot \underline{2\cdot 2}\cdot 2\cdot 3}+4\sqrt{\underline{2\cdot 2}\cdot 5}\\\\=2\cdot 3\sqrt{2 \cdot3}-3\cdot 7\sqrt{2\cdot 3}-2\cdot 2\sqrt{2\cdot 3}+2\cdot 4\sqrt{5}\\\\=6\sqrt{6}-21\sqrt{6}-4\sqrt{6}+8\sqrt{5}\\\\=-19\sqrt{6}+8\sqrt{5}$

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marishachu [46]

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Step-by-step explanation:

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2 years ago

Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

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2 years ago

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jonny [76]

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2 years ago

Is 32.725 greater or less than 32.735

AURORKA [14]

’32.725 is less than. 32.735

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3 years ago

Read 2 more answers

I need help with this pattern. Can u please tell me how u solved the pattern

andreyandreev [35.5K]

For the first one, repeat it: triangle, checkered square, hexagon

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hope this helped!

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2 years ago