Answer:
sometimes it can if there is nothing in the way.
It can be changes and improved to peoples liking or just in a natural way. I hope that kinda helped
<span>The right answer for this question is that during exercise, stored chemical energy is converted to energy that can be used for muscle movement. The particular chemical that is used for muscle movement is known as ATP, or adenosine triphosphate.</span>
It can be a chemical imbalance in the brain, a traumatic event, bad home life, etc.
Answer:

General Formulas and Concepts:
<u>Algebra I</u>
- Terms/Coefficients
- Functions
- Function Notation
- Factoring
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative Property [Addition/Subtraction]: ![\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28x%29%20%2B%20g%28x%29%5D%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28x%29%5D%20%2B%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bg%28x%29%5D)
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Product Rule]: ![\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Derivative Rule [Chain Rule]: ![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Explanation:
<u>Step 1: Define</u>
<em>Identify</em>
y = x(1 + x)³
<u>Step 2: Differentiate</u>
- Product Rule [Derivative Rule - Chain Rule]:
![\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5D%20%5Ccdot%20%281%20%2B%20x%29%5E3%20%2B%20x%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%281%20%2B%20x%29%5E3%5D%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%5B1%20%2B%20x%5D)
- Derivative Property [Addition/Subtraction]:
![\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5D%20%5Ccdot%20%281%20%2B%20x%29%5E3%20%2B%20x%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%281%20%2B%20x%29%5E3%5D%20%5Ccdot%20%28%5Cfrac%7Bd%7D%7Bdx%7D%5B1%5D%20%2B%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5D%29)
- Basic Power Rule:

- Simplify:

- Factor:
![\displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%281%20%2B%20x%29%5E2%20%5Cbigg%5B%20%281%20%2B%20x%29%20%2B%203x%20%5Cbigg%5D)
- Combine like terms:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e