Answer:
Vertex is (-5, -1)
(-3, 3) is a point on the parabola.
Step-by-step explanation:
f(x) = x² + 10x + 24
Let (h, k) be the vertex
h = -b/2a = -10/2(1) = -5
k = f(-5) = (-5)^2 + 10(-5) + 24
= 25 - 50 + 24 = -1
Vertex is (-5, -1)
Now, let x be some value different than -5, say -3
f(-3) = (-3)^2 + 10(-3) + 24
= 9 - 30 + 24 = 3
So, (-3, 3) is a point on the parabola.
X ^ (4/5)
Remember square root is 1/2 power. It has an index of 2 and power of 1. If you can remember this rule you can follow it for any other conversion.
Answer:
Step-by-step explanation:
x-y=7
-3x+9y=-39
Divide the second equation by 3
-x +3y = -13
Add this to the first equation
x-y=7
-x +3y = -13
----------------------
0x +2y = -6
Divide by 2
2y/2 = -6/2
y = -3
Now find x
x-y = 7
x -(-3) = 7
x+3 = 7
Subtract 3 from each side
x = 4
(4,-3)
Or by substitution
x-y=7
solve for x
x = 7+y
-3x+9y=-39
Substitute y+7 in for x
-3(7+y) +9y = -39
Distribute
-21 -3y +9y = -39
Combine like terms
-21 +6y = -39
Add 21 to each side
6y = -18
Given : Function f(x) = x⁵ + (x + 3)²
The Question is to find the image of the given function at x = -1
In order to find the image of a function for a given value, We need to substitute the value in the respective function
f(-1) = (-1)⁵ + (-1 + 3)²
f(-1) = -1 + (2)²
f(-1) = -1 + 4
f(-1) = 3
