Answer:
-4
Step-by-step explanation:
Slope = y2 - y1/x2 - x1
Given
x1 = 6
y1 = 2
x2 = 4
y2 = 10
Therefore
Slope = 10 - 2/4 - 6
= 8/-2
= -4
Answer:
1727 students
Step-by-step explanation:
Here we have the formula for sample size given as
![n = \frac{p(1-p)z^2}{ME^2}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Bp%281-p%29z%5E2%7D%7BME%5E2%7D)
Where:
p = Mean
ME = Margin of error = 3
z = z score
Therefore, we have
p = 150/240 = 0.625
z at 99 % = 2.575
ME =
3%
Therefore ![n = \frac{0.625(1-0.625)2.575^2}{0.03^2} = 1726.73](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B0.625%281-0.625%292.575%5E2%7D%7B0.03%5E2%7D%20%3D%201726.73)
The number of students Professor York have to sample to estimate the proportion of all Oxnard University students who watch more than 10 hours of television each week within ±3 percent with 99 percent confidence = 1727 students.
N + d = 20 (there are a total of 20 nickels and dimes).05n + .1d = 1.4 (total change equals $1.40)
Answer:
![a = 9\\b = 48\\c = -1](https://tex.z-dn.net/?f=a%20%3D%209%5C%5Cb%20%3D%2048%5C%5Cc%20%3D%20-1)
Step-by-step explanation:
We know that:
In a deck of 52 cards there are 4 aces.
Therefore the probability of obtaining an ace is:
P (x) = 4/52
The probability of not getting an ace is:
P ('x) = 1-4 / 52
P ('x) = 48/52
In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.
For a discrete random variable V, the expected value is defined as:
![E(V) = VP(V)](https://tex.z-dn.net/?f=E%28V%29%20%3D%20VP%28V%29)
Where V is the value that the random variable can take and P (V) is the probability that it takes that value.
We have the following equation for the expected value:
![E(V) = \frac{4}{52}(a) + \frac{b}{52}(c)](https://tex.z-dn.net/?f=E%28V%29%20%3D%20%5Cfrac%7B4%7D%7B52%7D%28a%29%20%2B%20%5Cfrac%7Bb%7D%7B52%7D%28c%29)
In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52
Therefore, expected value for V, the number of points obtained in the game is:
![E(V) = \frac{4}{52}(9) + \frac{48}{52}(-1)](https://tex.z-dn.net/?f=E%28V%29%20%3D%20%5Cfrac%7B4%7D%7B52%7D%289%29%20%2B%20%5Cfrac%7B48%7D%7B52%7D%28-1%29)
So:
![a = 9\\b = 48\\c = -1](https://tex.z-dn.net/?f=a%20%3D%209%5C%5Cb%20%3D%2048%5C%5Cc%20%3D%20-1)
Answer:
A = picture attached
B = 51 in²
Step-by-step explanation:
The picture attached is the answer for part A. You use the dimensions you already know from the first picture to fill in the net of the slice of pie.
Area of the triangle = 1/2 (base × height)
A = 1/2 (4 × 6) = 1/2 (24) = 12
The area of the triangle is 12. The top is a triangle, but the bottom is also a triangle with the same area. Therefore, the area of the two triangles combined is 24 in². Next, we have to find the area of the rectangle at the sides of the pie.
Area of rectangle = length × width
A = 5 × 2.5 = 12.5
Since there are two rectangles with the same area on both sides of the pie, we can double it and get 25 in². We still have one rectangle left, the one at the back of the pie.
A = 6 × 2.5 = 15
Add the areas altogether to get the answer.
24 + 12.5 + 15 = 51.5 in²
I hope this helps. Sorry if Part B's answer is wrong.