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amid [387]
3 years ago
11

Situation One

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

Step-by-step explanation:

Total no. of horses and chicken=24

C+H=24

Total no. horses be =24-C

Total no. legs=66

---66=4(24-C)+2C { As horses have 4 legs and chicken has 2 legs}

66=96-4c+2c

66-96=-2c

-30=-2C

Chicken=15

Therefore no. horses=24-C

=24-15

=9horses

There fore no. of chicken legs=15×2 = 30 legs

Therefore no. of horse legs=9×4=36 legs

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4 0
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Read 2 more answers
Find all possible rational zeros for f(x)=x^5-9x^4+24x^3-8x^2-33x+9 perform the following given that 2+ √3 is a zero
Arada [10]

Answer:

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wegnerkolmp2741o

Step-by-step explanation:

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