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amid [387]
3 years ago
11

Situation One

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

Step-by-step explanation:

Total no. of horses and chicken=24

C+H=24

Total no. horses be =24-C

Total no. legs=66

---66=4(24-C)+2C { As horses have 4 legs and chicken has 2 legs}

66=96-4c+2c

66-96=-2c

-30=-2C

Chicken=15

Therefore no. horses=24-C

=24-15

=9horses

There fore no. of chicken legs=15×2 = 30 legs

Therefore no. of horse legs=9×4=36 legs

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Problem 1.
Think of the outer rectangle by joining the two 5 in. sides with a segment.
Now you have an outer blue rectangle with a white rectangle missing.
For the outer rectangle:
The top and bottom sides measure 28 in.
The left and right sides measure 5 in. + 12 in. + 5 in. = 22 in.
Area of the outer rectangle = LW = 28 in. * 22 in. = 616 in.^2
Now look at the white square. You need to subtract this area from the outer rectangle.
area of white rectangle = LW = 12 in. * 15 in. = 180 in.^2

Subtract the areas:
616 in.^2 - 180 in.^2 = 436 in.^2

Answer:
<span>A. 436 Square Inches

Problem 2.
Do the same thing as for problem 1. Join the two 4 in. segments with a line.
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<span>Think of the outer rectangle by joining the two 4 in. sides with a segment.
Now you have an outer blue rectangle with a white rectangle missing.
For the outer rectangle:
The top and bottom sides measure 24 in.
The left and right sides measure 4 in. + 12 in. + 4 in. = 20 in.
Area of the outer rectangle = LW = 24 in. * 20 in. = 480 in.^2
Now look at the white square. You need to subtract this area from the outer rectangle.
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Subtract the areas:
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</span><span>B. 324 Square Inches</span>
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