We want the seconds to be converted in hours to work out the speed, so:
7200Seconds /60 / 60 =2 Hours
150 / 2 = 75
Therefore the car travels at 75kmh.
Hello,
-2x+2y=8==>y=x+4(1)
The perdicular passing trought (4,-2) is
y+2=-1(x-4)==>y=-x+2(2)
The intersection is
(1)-(2)==>2x+2=0==>x=-1 and y=-1+4=3
Q=(-1,3)
P=(4,-2)
Distance PQ= √(( -1-4)²+(3+2)²)=√50=7,0710678...
B because 10p means 10 × p
A compund inequality has two values.