A=bh/2, h=b-5 so
A=(b/2)(b-5)
A=(b^2-5b)/2 and A=42 so:
(b^2-5b)/2=42
b^2-5b=84
b^2-5b-84=0
b^2-12b+7b-84=0
b(b-12)+7(b-12)=0
(b+7)(b-12)=0 and since b>0
b=12m
Answer:
Step-by-step explanation:
Based on the given conditions, formulate:
Calculate the product or quotient: 240
get the result: 240
Answer: 240
To find this answer, we had to use the expression 80 * 3, therefore making it the answer.
Answer:
$400
Step-by-step explanation:
Let the initial total cost be represented = $X.
Hence, for 20 family members
= $ x/20 each .......1
Now that they are 25 members
= $x/25 each.......2
Each in the original group which is equation 1 owed $4 less.
That is,
x/20 - 4 ........ 3
Now equate 2 and 3
X/20 - 4/1 = X/25
Taking the LCM of both sides
X-80/20 = X/25
Cross multiply both sides
25( x-80 ) = 20x
25x-2000 = 20x
Collecting like terms
25x-20x = 2000
5x = 2000
Divide through by 5
X = 2000/5
X = 400
The total cost for the catered meal is $400.
To check if it was correct
Put 400 into equation 1 and 2 and then minus whatever you get from each other, you will get $4
From equation 1
400/20 = $20
From equation 2
400/25 =$16
$20-$16 = $4
Thanks
Answer:
12
Step-by-step explanation:
while f(x) = f(-1) then we can solve the equation
Y=-3(x-4)+3x
f(x)=-3(x-4)+3x
f(-1)=-3(x-4)+3x
=-3((-1)-4)+3(-1) = 12
Y=12