All categories

3 years ago

Hey this is my first post, does anyone know how to do this and find V?

Mathematics

2 answers:

Dvinal [7]3 years ago

8 0

Answer:

Step-by-step explanation:

8/1/2

8 divided by 1/2

8 x 2/1 = 16

Reil [10]3 years ago

3 0

Answer:

Step-by-step explanation:

P=8/V

1/2=8/V

do cross multiplication

2*8=V*1

16=V

You might be interested in

James and Bethany Morrison are celebrating their 10th anniversary by having a reception at a local reception hall. They have bud

ddd [48]

Answer: See Below

Step-by-step explanation:

Create the equation:

$34 times the number of people plus the $50 cleaning fee has to be less than or equal to $3500

34p + 50 <= 3500

34p <= 3450

p <= 101.470588....

We can have a part of a person attending the reception so we have to drop the remainder/decimal. Therefore the most amount of people that can attend the party and stay within budget is 101.

7 0

3 years ago

Jane bought 4 books, 3 cups, and 7 rungs. She paid $4 per book, $5 per cup, and $10 per ring. Estimate her change from $50 bill

vlada-n [284]

Hello!

Let's multiply each thing here.

4(4)=16

3(5)=15

15=16=31

50-31=29

Therefore, her change is $29.

I hope this helps!

8 0

3 years ago

Read 2 more answers

An accounting firm purchased a new digital camera that cost $2,500. The life of the camera is estimated to be 5 years. The total

lozanna [386]

2500-700 = 1800
1800/5 = 360

The annual depreciation of the camera is $360.

5 0

3 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

$P(x \ge 60) \approx P(z > 1.34)$