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ss7ja [257]
3 years ago
13

Hey this is my first post, does anyone know how to do this and find V?

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

16

Step-by-step explanation:

8/1/2

8 divided by 1/2

8 x 2/1 = 16

Reil [10]3 years ago
3 0

Answer:

Step-by-step explanation:

P=8/V

1/2=8/V

do cross multiplication

2*8=V*1

16=V

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How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove
BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

\dfrac{9}{n^2+1} =\dfrac{n+3}{4}

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\

The roots (zeros) are the  x  values where the graph intersects the x-axis. To find the roots (zeros), replace  y

with  0  and solve for  x. The graph of the equation is attached.

n  ≈  2.38450287

Hence, The equation has one extraneous solution which is n  ≈  2.38450287

For more information refer to the link.

brainly.com/question/15070282

5 0
3 years ago
6x4=8xN<br><br> How can I solve this
Nookie1986 [14]

6×4=24 right so than how many 8 can get you to 24, so you do 8,16,24 or 8×3 So it's 8×3=24 (Your welcome ^.^)


3 0
3 years ago
Read 2 more answers
A triangle has the area of 1/2(4x^2+29x+30)ft^2. If the base of the triangle is (x+6) ft, find the height of the triangle.
Paul [167]

Answer:

4x+5 ft

Step-by-step explanation:

1/2(4x²+29x+30) = 1/2 (x+6) * Height

Height = (4x²+29x+30) / (x+6) = (x+6) (4x+5) / (x+6) = 4x+5

3 0
3 years ago
Graphing the sine function <br> Graph y= Sine (x)<br><br> Please include picture
kramer

Step-by-step explanation:

hop it help ..........

........

8 0
3 years ago
One stats class consists of 52 women and 28 men. Assume the average exam score on Exam 1 was 74 (σ = 10.43; assume the whole cla
Svetllana [295]

Answer:

(A) What is the z- score of the sample mean?

The z- score of the sample mean is 0.0959

(B) Is this sample significantly different from the population?

No; at 0.05 alpha level (95% confidence) and (n-1 =79) degrees of freedom, the sample mean is NOT significantly different from the population mean.

Step -by- step explanation:

(A) To find the z- score of the sample mean,

X = 75 which is the raw score

¶ = 74 which is the population mean

S. D. = 10.43 which is the population standard deviation of/from the mean

Z = [X-¶] ÷ S. D.

Z = [75-74] ÷ 10.43 = 0.0959

Hence, the sample raw score of 75 is only 0.0959 standard deviations from the population mean. [This is close to the population mean value].

(B) To test for whether this sample is significantly different from the population, use the One Sample T- test. This parametric test compares the sample mean to the given population mean.

The estimated standard error of the mean is s/√n

S. E. = 16/√80 = 16/8.94 = 1.789

The Absolute (Calculated) t value is now: [75-74] ÷ 1.789 = 1 ÷ 1.789 = 0.559

Setting up the hypotheses,

Null hypothesis: Sample is not significantly different from population

Alternative hypothesis: Sample is significantly different from population

Having gotten T- cal, T- tab is found thus:

The Critical (Table) t value is found using

- a specific alpha or confidence level

- (n - 1) degrees of freedom; where n is the total number of observations or items in the population

- the standard t- distribution table

Alpha level = 0.05

1 - (0.05 ÷ 2) = 0.975

Checking the column of 0.975 on the t table and tracing it down to the row with 79 degrees of freedom;

The critical t value is 1.990

Since T- cal < T- tab (0.559 < 1.990), refute the alternative hypothesis and accept the null hypothesis.

Hence, with 95% confidence, it is derived that the sample is not significantly different from the population.

6 0
3 years ago
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