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Nadusha1986 [10]
4 years ago
5

Point D has coordinates (4, 1). What are the coordinates of Rx = 2(D)?

Mathematics
1 answer:
iris [78.8K]4 years ago
3 0
D^1 (0,1)
explanation: http://www.twinsburg.k12.oh.us/Downloads/geo%20ch9%20form%20assess%20KEYS.pdf
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Rlly need help on this ill give brainliest :)
Maksim231197 [3]

Answer:

3^15/5^16

Step-by-step explanation:

(3^3 x 3^6 x 5^-4) / (3^-6 x 5^12)

= (3^3 x 3^6 x 3^6) / (5^12 x 5^4)

= 3^15 / 5^16

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A clown has a silly string that is a 52cm long and magic scarf that is 28cm long.
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What is the equation of the line that passes through (6, 1) and is perpendicular to the line y 3x+2? CI) At what angle do the li
Andrews [41]

Answer with explanation:

The equation of any line with slope 'm' and passing through any point (x_1,y_1) is given by

y=mx+(y_1-mx_1)

As we know that the general equation of a line with slope 'm' is y=mx+c

Comparing with the given equation y=3x+2 we can conclude slope of the given line is m_1=3

Now we know that the product of slopes of perpendicular lines is -1

Mathematically we can write for perpendicular lines

m_1\times m_2=-1

Thus the slope of the required line is obtained from the above relation since it is given that they are perpendicular

3\times m_{2}=-1\\\\\therefore m_{2}=\frac{-1}{3}

Hence using the given and the obtained values the equation of the required line is

y=-\frac{1}{3}x+(1-\frac{-1}{3}\times 6)}\\\\y=\frac{-x}{3}+3

Part b)

The angle of intersection between 2 lines with slopes m_{1},m_2 is given by

\theta =tan^{-1}(\frac{m_2-m_1}{1+m_1m_2})

Comparing the equations of given lines

y=6x+3\\\\y=2x+3

with the standard equation we get

m_{1}=6\\\\m_{2}=2

Thus the angle of intersection becomes

\theta =tan^{-1}(\frac{2-6}{1+2\times6})=17.10

8 0
4 years ago
How long will it take you and 4 friends to paint the fence?
Ivahew [28]

Answer:

Check pdf

Step-by-step explanation:

Download pdf
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3 years ago
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