Answer:
Point form-
(3,-2)
Equation Form:
x=3, y=-2
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
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Answer: hello your question is incomplete attached below is the missing codes
Answer : It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement was not written in the main function
Step-by-step explanation:
It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement should be moved to the Main
<u><em>The correction is below </em></u>
{
double* p = new double;
hypotenuse(1.5, 2.0, p);
cout << "The hypotenuse is " << *p << endl;
}
Let's apply the law of sine to calculate angle C
sin(81)/26 = sin(C)/28
0.1646 = sin(C)/28 and sin(C) =1.063. Sine sin(α) cannot be > than 1, so this triangle is invalid
The circumcenter of a right angled triangle is midpoint of the hypotenuse side.
Determine the midpoint of the hypotenuse.

For y coordinate,

So, circumcenter of triangle is,
Answer:
the negative is what make it wrong
Step-by-step explanation: