Answer:
a) The interval for those who want to go out earlier is between 43.008 and 46.592
b) The interval for those who want to go out later is between 47.9232 and 51.9168
Step-by-step explanation:
Given that:
Sample size (n) =128,
Margin of error (e) = ±4% =
a) The probability of those who wanted to get out earlier (p) = 35% = 0.35
The mean of the distribution (μ) = np = 128 * 0.35 = 44.8
The margin of error = ± 4% of 448 = 0.04 × 44.8 = ± 1.792
The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)
b) The probability of those who wanted to start school get out later (p) = 39% = 0.39
The mean of the distribution (μ) = np = 128 * 0.39 = 49.92
The margin of error = ± 4% of 448 = 0.04 × 49.92 = ± 1.9968
The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)
The way for those who want to go out earlier to win if the vote is counted is if those who do not have any opinion vote that they want to go earlier
So the modal value is most commonly known as mode, or the most common number in a data set. So the most common number in this stem-and-leaf plot is 137
The modal value is 137
Hopes this helps!
<span>1.) The polygon whose vertices in the coordinate plane are (-2,3) (2,3) (2,0) (-2,0) is a rectangle with length = 4 units and width = 3 units.
Therefore, only equiangular.
2.) </span>T<span>he polygon whose vertices in the coordinate plane are (3,3) (5,0) (5,-3) (1,-3) (1,0) is a triangle on top of a rectangle which is neither equilateral nor equiangular nor regular.
i.e. none of the above.
3.) </span>T<span>he polygon whose vertices in the coordinate plane are (5,0) (5,-3) (1,-3) (1,0) is a rectangle.
Therefore, it is only equiangular.
</span>
Answer:
After 5 minutes Kaitlyn have to mow 5,250 square feet of lawn.
Step-by-step explanation:
We are given the following in the question:
Total area of lawn = 5,625 square feet
Rate of mowing lawn = 75 square feet each minute
Area of lawn mowed in 5 minutes =
Square feet does Kaitlyn still have to mow after 5 minutes
Thus, after 5 minutes Kaitlyn have to mow 5,250 square feet of lawn.
