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2 years ago

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Chess Club is selling stuffed animals for Valentine's Day. It costs the council $2.00 per stuffed animal and a one time shipping

fee of $25.00. They sell the animals for $4.00 each. How many stuffed animals do they need to sell to break even?

1 answer:

gregori [183]2 years ago

5 0

Answer:

about six of them

Step-by-step explanation:

You might be interested in

Solve the system of equations.

Xelga [282]

Answer:

b. x=1, y=2, z=3

Step-by-step explanation:

The system of equations ...

3x +2y +z = 10
9x -6y +z = 0
x -y -3z = -10

has solution (x, y, z) = (1, 2, 3) . . . . matches choice B.

_____

While it is convenient to solve this using a graphing calculator or web site, one can easily solve the system by hand.

Subtract the second equation from 3 times the first:

3(3x +2y +z) -(9x -6y +z) = 3(10) -(0)

12y + 2z = 30 . . . . simplify

Dividing this result by 2 gives ...

6y +z = 15 . . . . . . [eq4]

Subtract 3 times the third equation from the first:

(3x +2y +z) -3(x -y -3z) = (10) -3(-10)

5y +10z = 40 . . . . simplify

y + 2z = 8 . . . . . . . divide by 5 . . . . . [eq5]

The two equations [eq4] and [eq5] can be solved any of the ways you usually solve two equations in two variables. Here, we'll use the first equation to write an expression for z that we can substitute into the second equation.

z = 15 -6y . . . . . subtract 6y from [eq4]

y + 2(15 -6y) = 8 . . . . . substitute for z in [eq5]

-11y +30 = 8 . . . . . simplify

-11y = -22 . . . . . . . subtract 30

y = 2 . . . . . . . . . . . divide by the coefficient of y

z = 15 -6(2) = 3 . . . . substitute for y in our equation for z

Substituting these values for y and z into the third original equation gives ...

x - 2 -3(3) = -10

x -11 = -10 . . . . . . . . simplify

x = 1 . . . . . . . . . . . . add 11

The solution to the above system of equations is (x, y, z) = (1, 2, 3).

_____

<em>Comment on the problem statement</em>

Math is generally unforgiving of imprecision. The given system of equations has no variable "z", and some other typos are apparently involved. That is why we rewrote the system to the equations shown above.

It is very easy to mistake z for 2, or g for 9, or o for 0, or 1 for 7. There are other confusions that are possible, as well. Letters I (eye) and l (ell) are easily confused, and may be confused with 1 (one) as well. Sometimes y and 4, or 4 and 9, can also be written so as to be difficult to tell apart. Great care must be taken when handwriting these symbols.

7 0

3 years ago

gabriel put 6000 in a 2 year CD paying 4% interest, compounded monthly. After 2 years , he withdrew all his money. what was the

shutvik [7]

amount after 2 years = 6000(1 + (0.04/12))^24 = 6498.86

7 0

2 years ago

Read 2 more answers

A man buys 6 ½ of petrol daily. How many litres of petrol does he purchase in six days

nalin [4]

Answer:

39 liters

Step-by-step explanation:

6.5×6=39

so 39 litres

6 0

2 years ago

Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...

Strike441 [17]

Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

$\displaystle -3x -1, \, 4x +4, \, 11x + 9 \dots$

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

$\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}$

Find the common difference by subtracting the first term from the second:

$d = (4x+4) - (-3x - 1)$

Distribute:

$d = (4x + 4) + (3x + 1)$

Combine like terms. Hence:

$d = 7x + 5$

The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

$\displaystyle x_n = a + d(n-1)$

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

$\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)$

To find the 13th term, let <em>n</em> = 13. Hence:

$\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)$

Simplify:

$\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}$

The 13th term is 81<em>x</em> + 59.

3 0

2 years ago

What is the value of the expression if m = –5 and n = 3? Negative StartFraction 24 Over 25 EndFraction Negative StartFraction 4

KatRina [158]

You can use the fact that a number raised to negative powers can be written as 1 divided by that number raised to positive number.

The value of the given expression when m = -5 and n= 3 is $-\dfrac{2}{5}$

<h3>How can we rewrite a number raised to negative power?</h3>

Suppose we've got $a^{-b}$ . then it can be rewritten as

$a^{-b} = \dfrac{1}{a^b}$

It is because $a^0 = 1$ for any a except 0, and that $\dfrac{a^0}{a^b} = a^{0-b} = a^{-b}$

If base are same and there is multiplication, then there will be addition in power.

Also, know the fact that if base are same and there is division, there will be subtraction in power(subtracting since that denominator when goes up, its power gets negated(gets negative sign to the existing power)

Thus,

$a^b \timesa ^c = a^{b+c}\\\\\dfrac{a^b}{a^c} = a^{b-c}$

<h3>Using above method to simplify the given expression before evaluating</h3>

The given expression is $\dfrac{2m^{-1}n^5}{3m^0n^4} = \dfrac{2n^5}{3m^0m^1n^4} = \dfrac{2n^5}{3mn^4} = \dfrac{2n^{5-4}}{3m} = \dfrac{2n^1}{3m} = \dfrac{2n}{3m}$

Putting m = -5 and n=3, we get:

$\dfrac{2\times 3}{3 \times -5} = -\dfrac{2}{5}$

Thus,

The value of the given expression when m = -5 and n= 3 is $-\dfrac{2}{5}$

Learn more about base and exponent(power) here:

brainly.com/question/847241

4 0

2 years ago