You didn’t add any pictures so how could i help you with this?
Answer:
<h2>6</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>given:</h3>
<h3>let's solve:</h3>
- substitute the value of y:2²-2.2+6
- simplify exponent:4-2.2+6
- simplify multiplication;4-4+6
- simplify addition:4+2
- simplify addition:6
The distance between the point (3, 5) and a line with the equation 5x – 3y + 10 = 0 will be 10 / √(34) units.
<h3>What is the distance between a point and a line?</h3>
Let (x₁, y₁) be the point and ax + by + c = 0 be the line.
Then the distance between a point and a line will be

The point (3, 5) and a line with the equation 5x – 3y + 10 = 0.
Then the distance between them will be

Learn more about the distance between a point and a line here;
brainly.com/question/11558698
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