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Murrr4er [49]
3 years ago
9

PLEASE ANSWER ASAP WILL GIVE BRAINLIEST

Mathematics
2 answers:
Lapatulllka [165]3 years ago
5 0
10 is the mean I’m pretty sure
yuradex [85]3 years ago
4 0
The mean should be 10
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Find the standard form of the quadratic equation: f(x)=(2x-1)(x+4)
katrin [286]

Answer:

f(x) =  2x ^{2}  + 7x  -  4

Step-by-step explanation:

\because \: f(x) = (2x - 1)(x + 4) \\  \therefore \:f(x) =  2x(x + 4)  - 1(x + 4) \\ \therefore \:f(x) =  2x ^{2}  + 8x -   x  -  4 \\ \therefore \:f(x) =  2x ^{2}  + 7x  -  4 \\

3 0
3 years ago
Circle o has a circumference of 28.3 cm. What is the length of the radius r?
andreyandreev [35.5K]
Circumference = 2Pi * r

28.3cm = 2pi * r ( Isolate r )
28.3cm / 2pi = r
R = 4.504

To verify work we can plug 4.504 back into the equations.

Circumference = 2pi*4.504 ~ 28.299 Which is true !
4 0
2 years ago
In circle pp, ad¯¯¯¯¯ad¯ is a diameter and bc¯¯¯¯¯bc¯ is perpendicular to ad¯¯¯¯¯ad¯ at ee. if pd=7pd=7 and ae=4ae=4, find cece.
kvv77 [185]
See the attached figure.

<span>ad is a diameter of the circle with center p
</span>
∵ pd = radius = 7 ⇒⇒⇒ ∴ ad = 2 * radius  = 2 * 7 = 14
∵ ae = 4 ⇒⇒⇒ ∴ ed = ad - ae = 14 - 4 = 10
∵ ad is a diameter
Δ acd is a triangle drawn in a half circle
∴ Δ acd is a right triangle at c
∵ bc ⊥ ad at point e
By applying euclid's theorem inside Δ acd
∴ ce² = ae * ed
∴ ce² = 4 * 10 = 40
∴ ce = √40 = 2√10 ≈ 6.325


3 0
3 years ago
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Korolek [52]
3-18x & 0 0.2-0.1x do you have. A picks
5 0
2 years ago
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What is three over two x plus three equal to zero
nataly862011 [7]

QUESTION → \frac{3}{2}x + 3 = 0

Start by subtracting 3 from both sides to get \frac{3}{2}x = -3.

Now multiply both sides by the reciprocal of 3/2, which is 2/3.

On the left, we have x, and on the right, -3(2/3) is -2.

So we have x = -2.

7 0
3 years ago
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