there are 98 girls at Ross elementary there are 15 less boys then girls how many boys and girls are at Ross elementary

Wright the ratio 4.5 : 2.35 in the form n : 1

sergeinik [125]

Answer:

$\frac{9}{47}: 1$

Step-by-step explanation:

you can divide both sides by 2.35 to get the right side to be 1:

$4.5: 2.35\\\frac{9}{47}: 1$

6 0

3 years ago

A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time student

Butoxors [25]

Answer: $(21.541,\ 23.059)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : $n=240$ , which is a large sample , so we apply z-test .

Sample mean : $\overline{x}=22.3$

Standard deviation : $\sigma= 6$

Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.960$

Now, a confidence interval at the 95% level of confidence will be :-

$22.3\pm(1.960)\dfrac{6}{\sqrt{240}}\\\\\approx22.3\pm0.759\\\\=(22.3-0.759,\ 22.3+0.759)\\\\=(21.541,\ 23.059)$

7 0

3 years ago

Which net represents the figure. Plz help meeeeeeeee

Goshia [24]

The fourth graph or D (the one in the bottom right corner) this is because a pyramid consists of four triangles and one square at the bottom.

Correct me if wrong
Have a nice day :D
~Hackermcpe

3 0

3 years ago

Read 2 more answers

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: