Volume of first oil = A, volume of second oil = B, volume of mixture = M
A = ?, B = 4l, M = A + B
40%A + 25%B = 30%M
40%A + 25%4l = 30%(A+4l)
<span>40%A + 25%4l = 30%A + 30%4l
40A + 100l = 30A + 120l
40A - 30 A = 120l - 100l
10A = 20l
A = 2l
</span>
Answer: 2 litres of 40% oil dressing.
Also note: That's an approximation, because the volumes are not strictly additive. For example: mixing 50ml pure ethanol with 50ml water will give you about 95ml of mixture. To get an accurate answer, you'd have to measure the volume of the final mixture and then divide your total oil content by that<span>.</span>
The answer is:
4x+2y=11} 4x+2y=11} x=2-2y
x-2=-2y } x+2y=2 } x=2-2(-3/6)
x=2-(-6/6)
4(2-2y)+2y=11 x=2-(-1)
8-8y+2y=11 x=3
8-6y=11
-6y=11-8
-6y=3/-6
y=-3/6=-1/2
So for my opinion the solution is A.(3,-1/2)
Answer:
not sure about 1
for number 2 it is 5 over 4 . for y, 5 10 15 20 is a multiple of 5 so the change is 5. for x, 4 8 12 16 is a multiple of 4 so the change is 4.
Answer:
πr²= 12.56
r²=12.56/3.14 = 4
r= 2
therefore , diameter = 2r = 2×2= 4 mm
