Which number line shows the inequality n<

Given: ST = VT RT= UT <br>Prove: RST UVT

natka813 [3]

Step-by-step explanation:

ST ≅ VT
RT ≅ UT

∠UTV ≅ ∠ RTS as vertical angles

The information you have is the two sides and the included angle are congruent.

<u>It is good to prove:</u>

ΔRST ≅ ΔUVT by SAS postulate

5 0

3 years ago

According to a study, 50,000 bachelor degrees in business were awarded in 1990 and 100,000 were awarded in 2000. If the number o

joja [24]

For every elapsed year (X), 5000 bachelor degrees in business will increase (Y).

<h3><u>Linear functions</u></h3>

To determine, if the number of bachelor degrees in business continues to grow linearly, what will be the growth parameter in said linear equation, the following calculation must be performed:

(100000 - 50000) / (2000 - 1990) = Y
50000 / 10 = Y
5000 = Y

Therefore, for every elapsed year (X), 5000 bachelor degrees in business will increase (Y).

Learn more about linear functions in brainly.com/question/17058347

8 0

3 years ago

11. In the same "Insurance Problem". the insurance company has 50,000 customers

KiRa [710]

Well, all you have to do is multiply the amount of customers times the amount they pay each month. 50,000 x 30 = 1,500,000

So, your answer is $1,500,000 per month

5 0

4 years ago

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

As

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$