I don’t know the answer but I noticed you name and saw it. Nice name from shiba.
Answer:
1. -10x^2-x+6-10x 2-x+6 = -10x^2 - 22x + 12
2. 10x^2-510x 2-5 = 10x^2 - 1020x - 5
Step-by-step explanation:
hope this helps
if i did something wrong let me know so i can fix my answer
#Virgo2007
Answer:
Step-by-step explanation:
Average rate of change is just using the slope formula: (y2-y1)/(x2-x1).
From the steps shown in the table given, we can conclude that: D. in solving the equation, the subtraction property of equality was not applied.
<h3>What is the Subtraction Property of Equality?</h3>
If a + b = c, to apply the subtraction property of equality so that b is moved to the other side of the equation, we would have:
a + b - b = c - b
a = c - b
Thus, from the table given, the none of the steps showed that the subtraction property of equality was applied in solving the equation, so, the answer is: D.
Learn more about the subtraction property of equality on:
brainly.com/question/1601404
#SPJ1
Answer:
The maximum variance is 250.
Step-by-step explanation:
Consider the provided function.
![V(x)=1000x(1-x)](https://tex.z-dn.net/?f=V%28x%29%3D1000x%281-x%29)
![V(x)=1000x-1000x^2](https://tex.z-dn.net/?f=V%28x%29%3D1000x-1000x%5E2)
Differentiate the above function as shown:
![V'(x)=1000-2000x](https://tex.z-dn.net/?f=V%27%28x%29%3D1000-2000x)
The double derivative of the provided function is:
![V''(x)=-2000](https://tex.z-dn.net/?f=V%27%27%28x%29%3D-2000)
To find maximum variance set first derivative equal to 0.
![1000-2000x=0](https://tex.z-dn.net/?f=1000-2000x%3D0)
![x=\frac{1}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B2%7D)
The double derivative of the function at
is less than 0.
Therefore,
is a point of maximum.
Thus the maximum variance is:
![V(x)=1000(\frac{1}{2})-1000{\frac{1}{2}}^2](https://tex.z-dn.net/?f=V%28x%29%3D1000%28%5Cfrac%7B1%7D%7B2%7D%29-1000%7B%5Cfrac%7B1%7D%7B2%7D%7D%5E2)
![V(x)=250](https://tex.z-dn.net/?f=V%28x%29%3D250)
Hence, the maximum variance is 250.