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iris [78.8K]
3 years ago
6

If ASTU is similar to AXYZ, the sides of ASTU must be congruent to the

Mathematics
1 answer:
miss Akunina [59]3 years ago
4 0
It’s false


..............
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Bridget went fishing with her dad. Bridget Bridget caught the first fish of the day, another was 2 more than 3 times the weight
Arturiano [62]

Answer:

Bridget's first fish =f = 5 ounces

Bridget's dad first fish weighs 17 ounces

Step-by-step explanation:

Solution:

Bridget's fishes:

f ounces

2f ounces

3f+2 ounces

1/2f ounces

3/5f ounces

Total= f +2f + (3f+2) + 1/2f +3/5f

=3f + 3f + 2 + 5f+6f/10

=6f + 2 + 11f/10

=60f+11f/10 +2

=71/10f +2

Bridget's dad fishes

3f+2

4/5f

2f+4

1/2f

Total =(3f+2) + (2f+4) + 4/5f +1/2f

=3f+2+2f+4 + 8f+5f/10

=5f + 6 + 13/10f

= 50f+13f/10 + 6

=63/10f +6

Equate the total weight

71/10f +2=63/10f +6

Collect like terms

71/10f - 63/10f =6-2

71f-63f/10 = 4

8f/10=4

Cross product

8f=40

Divide both sides by 8

f=5

Bridget's first fish =f = 5 ounces

Bridget's dad first fish = 3f +2

=3(5)+2

=15+2

=17 ounces

Bridget's dad first fish weighs 17 ounces

8 0
3 years ago
I need help with those two problems. Thanks for helping!
natima [27]
Answer:
1. To solve for “b,” you must isolate the variable. The result is 2A/h=b
2. In this question, we must solve for “F.” 9/5(C)+32=F
4 0
3 years ago
Change the expression to a single square root, or its opposite:
aleksley [76]

Answer:

a)2\sqrt{2}=\sqrt{8}

b)-7\sqrt{3} =-\sqrt{147}

c)\frac{1}{3} \sqrt{18b}  =\sqrt{2.b}

d)5\sqrt{y} =\sqrt{25y}

e)-6\sqrt{2a}  =-\sqrt{72a}

f)-0.1\sqrt{200c}=-  \sqrt{2c

Step-by-step explanation:

a) 2\sqrt{2}=( \sqrt{2}  )^2.\sqrt{2}=(\sqrt{2})^3 = \sqrt{2^3} =\sqrt{8}

b)-7\sqrt{3} =-(\sqrt{7} )^2\sqrt{3} =-\sqrt{7^2.3} =-\sqrt{147}

c)\frac{1}{3} \sqrt{18b} =\frac{1}{3} \sqrt{9.2.b} =\frac{1}{3} \sqrt{3^2.2.b} =\frac{1}{3} \times 3\sqrt{2.b} =\sqrt{2.b}

d)5\sqrt{y} =\sqrt{5^2} \sqrt{y}=\sqrt{25y}

e)-6\sqrt{2a} =-\sqrt{6^2}\sqrt{2a}  = -\sqrt{36.2a} =-\sqrt{72a}

f)-0.1\sqrt{200c}=-\frac{1}{10}  \sqrt{10^2.2c} =-\frac{1}{10}\times10  \sqrt{2c}=-  \sqrt{2c

4 0
3 years ago
Need help plzzzz....need this done by today
ddd [48]

For this case, we must indicate which of the given graphs corresponds to the following inequality:

y\geq 1-3x

If we substitute the point(x, y) = (0,0) we have:

0> = 1-3 (0)\\0> = 1

It is not met, so we discard options A and C.

It is observed that the lines of option B and D correspond to the equationy = 1-3x. But the dotted line of option B indicates that the region given by: y> 1-3x is plotted

Thus, the region that indicatesy\geq 1-3x is option D

Answer:

Option D


5 0
3 years ago
From the following figures, find the values of 'a', 'b', 'c': 'd', 'e' and 'f':​
Dvinal [7]

Answer:

a=110 b=35 c= 10 d=55 e=14 f=10

Step-by-step explanation:

a = 11c , 180-70=110

b=2*35 =70

c= 11*10=110

2d=110 , d=55

e=5*14=70

7f=70 , f=10

5 0
3 years ago
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