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Ainat [17]
3 years ago
12

You want to rent a television. Company A charges $25 per week plus a one-time fee of $52. Company B charges $37 per week plus a

one-time fee of $16. After how many weeks are the total costs the same at both companies?
Mathematics
1 answer:
RUDIKE [14]3 years ago
8 0
52+25=77+25=102+25=127
16+36=53+37=90+37=127
Answer 3 weeks
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A certain plant grows 1 3/4 inches every week how long will it take the plant to grow 9 1/4 inches. HELPPP I’m dumb
GREYUIT [131]
It only takes 13/4 days inn week
3 0
3 years ago
HELP PLSSSSSESSSSSSSSSSSS
bekas [8.4K]

Answer:

Step-by-step explanation:

10(3)+2(10)(4)+2(3)(4)=30+80+24

                                =134

8 0
2 years ago
Which graph represents a function that is decreasing at a nonconstant rate?
Tasya [4]

Answer: C

since the line isn't straight, the slope/function is decreasing but not at a constant rate

3 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
2 years ago
Evaluate x ÷ y for x = 3 and y = 12.
eduard

Answer:

1/4 or 0.25

Step-by-step explanation:

Lets plug x and y into the equation. We now have 3/12, which would be equal to 1/4 or 0.25

6 0
3 years ago
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