Answer:
line1:y=2x+3
Gradient1=2
Let line2 be the line passes through (-4,1)and perpendicular to line1.
Because line2 and line1 are perpendicular, (gradient of line2) (gradient of line1) =-1
Gradient of line2=-1/2
Equation of line2:y-y1 =m(x-x1)
:y-1 =(-1/2)[x-(-4)]
:(y-1)(-2)=(x+4)
:-2y+2 =x+4
:-2y+2-x-4=0
:-x-2y-2 =0
:x+2y+2 =0
*notes:gradient=m
Answer:
always true.
the expression will always be equal to +5 because -p+p is zero
at any given value to p, the value is constantly +5
Answer:
4 miles
Step-by-step explanation:
Answer:
The system of linear equations are
and 
Step-by-step explanation:
Given : The number of students who chose lunch was 5 more than the number of students who chose breakfast. Let x represent the number of students who chose breakfast and y represent the number of students who chose lunch.
(50 students picked, 25 picked dinner the rest picked lunch and breakfast)
To find : Write a system of linear equations that represents the numbers of students who chose breakfast and lunch ?
Solution :
The number of students who chose breakfast be 'x'
The number of students who chose lunch be 'y'.
The number of students who chose lunch was 5 more than the number of students who chose breakfast.
i.e. 
Now, Total student were 50 and 25 picked dinner the rest picked lunch and breakfast i.e. 25.
So, 
Therefore, the system of linear equations are
and 