If the question in how many WERE in her bouquet then it’s 15 bc that’s how many WERE originally in there. i’d it’s how many she has now it’s 7 flowers unless they are counting the flowers she used to make her bouquet then it’s 9 sorry if this is confusing
Answer:
Around 364
Step-by-step explanation:
So to fund the answer, you need to find how much they can eat per minute: 32/5 = 6.4 (around 6 lunches)
Then you multiply this by 57: 57x6.4 = 364.8
Answer:
(- p) × (- p) × (- p)
Step-by-step explanation:
(-p)³
(- p) × (- p) × (- p)
Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Ok there are 48000 mL in 48L.
