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3 years ago

I would do 100 points but i cant i only have 33 please give me the right answer or i will report

Mathematics

1 answer:

seraphim [82]3 years ago

4 0

Answer:

height
width
id-k
width
base
square

Step-by-step explanation:

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1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

2 years ago

Read 2 more answers

Find the surface area of each figure?Please help

kolbaska11 [484]

--------------------------------------------------
Surface area of the cube
--------------------------------------------------
6(2.5 x 2.5) = 37.5m²

(* Each area is 2.5 x 2.5, and there are 6 sides to the cube)

--------------------------------------------------
Surface area of the rectangle prism
--------------------------------------------------
2(11 x 7) + 2(9 x 7) + 2(9 x 11) = 478m²

(* The opposite side of the rectangle area is the same, therefore x2)

--------------------------------------------------
Overlapping area
--------------------------------------------------
2.5 x 2.5 = 6.25m²

--------------------------------------------------
Surface area of the composite figure
--------------------------------------------------
37.5 + 478 - 2(6.25) = 503m²

(* The bottom of the cube and the top of the rectangle prism overlapped, so the area is overlapped twice, minus 2 times of that area)

--------------------------------------------------
Answer: 503m²
--------------------------------------------------

4 0

2 years ago

A car travels 30 1/5 miles in 2/3 of an hour. Whwt is the average speed, in miles per hour, of the car

LiRa [457]

Answer:

45 3/10 mph

Step-by-step explanation:

30 1/5 /2 = 15 1/10

15 1/10 x 3 = 45 3/10 mph

8 0

2 years ago

5x to the second power-13x +6 guys answer only

Thepotemich [5.8K]

Answer:

-138

Step-by-step explanation:

6 0

2 years ago

What is the x? 4x+50=150

swat32

Answer:

x = 25

Step-by-step explanation:

Given

4x + 50 = 150 ( subtract 50 from both sides )

4x = 100 ( divide both sides by 4 )

x = 25

8 0

2 years ago

Read 2 more answers