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gtnhenbr [62]
4 years ago
14

Geometry help ASAP 15 points Need help to find A and B

Mathematics
1 answer:
Marta_Voda [28]4 years ago
6 0
sin60^o= \frac{a}{2 \sqrt{2} }  \ \ \to  \ a=2 \sqrt{2} *sin60^o=2 \sqrt{2}* \frac{ \sqrt{3}}{2}= \sqrt{6}     \\  \\ cos60^o =  \frac{b}{2 \sqrt{2} }  \ \ \to  \ b=2 \sqrt{2} *cos60^o=2 \sqrt{2}*0.5= \sqrt{2}

Answer: a=√6,  b=√2
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A room is 16 feet, 8 inches long and the ratio of lenght to the widthis 4 to 5. what is the width of the room?
dedylja [7]

Answer:

The width is 20 feet 10 inches.

8 0
2 years ago
Does anyone know how to solve this?
erik [133]

Answer:

A point in polar coordinates is written as (R, θ)

If we want to transform this point to rectangular coordinates, we get:

x = R*cos(θ)

y = R*sin(θ)

Now we can remember that the sine and cosine functions have a period of 2*pi, then:

cos(θ) = cos(θ + 2*pi)

or:

cos(θ) = cos(θ + 2*pi + 2*pi)

and so on.

Then the point (R, θ) is the same as (R, θ + 2*pi) and (R, θ + k*(2*pi))

where k can be any integer number.

Then if we have a point in polar coordinates:

(-4, -5*π/3)

Then another two polar representations of this point are:

(-4, -5*π/3 + 2*π) = (-4, -5*π/3 + 6*π/3) = (-4, π/3)

Now we can not add 2*π (nor subtract) because we would have an angle outside the range [-2*π, 2*π]

For example, if we have:

(-4, π/3 + 2*π) = (-4, 7*π/3)

And we can not change the value of the radius and get the coordinates for the same point.

So another representation could be something like:

(-8/2, π/3)

Where i just wrote -4 in another way.

Now, a really important point.

When working with polar coordinates, we always use R as a positive number (here you can see that R is negative) so this is not the standard notation for the polar representation of a point.

8 0
3 years ago
Where is the blue dot on the number line?
earnstyle [38]

<em>Answer:</em>

–6.8

<em>Method:</em>

Counting backwards from –7 to –6.5

5 0
2 years ago
Read 2 more answers
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Masteriza [31]

Answer: B: 24q+48r

Step-by-step explanation: 6(4q+8r)

=(6)(4q+8r)

=(6)(4q)+(6)(8r)

=24q+48r

 

8 0
3 years ago
Item 3 The Hampton family used 17,158 kilowatts of electricity last year. They used about the same amount of electricity each we
katen-ka-za [31]
17,158/52= 329.96 rounded to the nearest tenth is 330
7 0
3 years ago
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