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gtnhenbr [62]
4 years ago
14

Geometry help ASAP 15 points Need help to find A and B

Mathematics
1 answer:
Marta_Voda [28]4 years ago
6 0
sin60^o= \frac{a}{2 \sqrt{2} }  \ \ \to  \ a=2 \sqrt{2} *sin60^o=2 \sqrt{2}* \frac{ \sqrt{3}}{2}= \sqrt{6}     \\  \\ cos60^o =  \frac{b}{2 \sqrt{2} }  \ \ \to  \ b=2 \sqrt{2} *cos60^o=2 \sqrt{2}*0.5= \sqrt{2}

Answer: a=√6,  b=√2
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m_a_m_a [10]

Answer:

a c d

Step-by-step explanation:

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While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between
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Step-by-step explanation:

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4 years ago
An article in an educational journal discussing a non-conventional high school reading program reports a 95% confidence interval
Maksim231197 [3]

Answer:

The margin of error associated with this confidence interval is 20

Step-by-step explanation:

A confidence interval has two bounds, a lower bound and an upper bound. The interval is symmetric, which means that the margin of error is the difference between these two bounds(upper - lower), divided by 2.

In this problem, we have that:

Lower bound: 520

Upper bound: 560

Determine the margin of error associated with this confidence interval.

(560 - 520)/2 = 20

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6 0
3 years ago
Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa
xxMikexx [17]

Answer:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      32   18    50

Medium                                 68     7    75

Large                                     89    11    100

_____________________________________

Total                                     189    36   225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1:  NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*189}{225}=42

E_{2} =\frac{50*36}{225}=8

E_{3} =\frac{75*189}{225}=63

E_{4} =\frac{75*36}{225}=12

E_{5} =\frac{100*189}{225}=84

E_{6} =\frac{100*36}{225}=16

And the expected values are given by:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      42    8    50

Medium                                 63     12    75

Large                                     84    16    100

_____________________________________

Total                                     189    36   225

And now we can calculate the statistic:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

3 0
4 years ago
If you subtract 12<br> from my number and<br> multiply the difference by -3,<br> the result is -54.
worty [1.4K]

Answer:

the answer is 30

Step-by-step explanation:

Let the number be x

- 3 (x - 12) = - 54

-3x + 36 = -54

-3x = -54 - 36

-3x = -90

x = -90/-3

x = 30

4 0
3 years ago
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