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Ymorist [56]
3 years ago
9

Can someone help me with this. Will Mark brainliest.

Mathematics
1 answer:
Anon25 [30]3 years ago
4 0

Answer:

the distance between the two points is √130.

Step-by-step explanation:

a^2 + b^2 = c^2

a^2 = 9^2 = 81

b^2 = 7^2 = 49

c^2 = 81 + 49 = 130

c = √130

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5(3)+2y=20<br><br> What’s the y factor?
Vera_Pavlovna [14]

Answer:

The answer should be y=2.5

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14-6=8 what is the tens factor used 10- what = what
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Speak Engrish son lol what=what

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Write the function that describes the line that has a y-intercept of -3 and a slope of 2/3
Ugo [173]

The function that describes the line that has a y-intercept of -3 and a slope of 2/3 is y = 2/3x - 3. Hope that helps!

8 0
3 years ago
Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.3 cus
likoan [24]

Given Information:

Average customer arrival = λ =2.3 customers/hour

Average consultant time1 = μ  = 8 minutes/customer

Average consultant time2 = μ  = 10 minutes/customer

Cost of consultants service = $16

Cost of customer waiting time = $25

Required  Information:

Use one consultant with an average service time of 8 minutes/customer or use two consultants, each with average service time of 10 minutes/customer ?

Answer:

it is recommended to use one consultant with an average service time of 8 minutes/customer.

Step-by-step explanation:

Convert the average consultant time to hours/customer

Average consultant time1 = μ  = 60/8 = 7.5 hours/customer

Average consultant time2 = μ  = 60/10 = 6 hours/customer

Single consultant queuing model:

Calculations for one consultant

Average no. of customers waiting for service = Lq = λ²/μ(μ-λ)

Average no. of customers waiting for service = Lq = (2.3)²/7.5(7.5 - 2.5)

Average no. of customers waiting for service = Lq = 0.1356

Average no. of customers in the system = L = Lq + λ/μ

Average no. of customers in the system = L = 0.1356 + 2.3/7.5

Average no. of customers in the system = L = 0.442

Total cost = (customer waiting time cost)*L + consultant service cost

Total cost = $25*0.442 + $16

Total cost = $27.05

Multi consultant queuing model:

Calculations for two consultants

Average no. of customers waiting for service = Lq = ((λ/μ)^k(λμ)/(k -1)(kμ - λ))*P₀

Where k = 2 is the number of consultants and P₀ is the probability that all of the k consultants are idle. The value of P₀  can be found in the tables with λ/μ = 2.3/6 = 0.38 and k = 2,  P₀ ≅ 0.685

Average no. of customers waiting for service = Lq = (2.3/6)²(2.3*6)/(2-1)(2*6 - 2.3)*0.685

Average no. of customers waiting for service = Lq = 0.1431

Average no. of customers in the system = L = Lq + λ/μ

Average no. of customers in the system = L = 0.1431 + 2.3/6

Average no. of customers in the system = L = 0.5264

Total cost = (customer waiting time cost)*L + consultant service cost

Total cost = $25*0.5264 + ($16)*2 (since there are 2 consultants now)

Total cost = $45.16

Conclusion:

Therefore, it is recommended to use one consultant with an average service time of 8 minutes per customer since the total cost is less than the other option.

3 0
3 years ago
The distances (y), in miles, of two cars from their starting points at certain times (x), in hours, are shown by the equations b
Harlamova29_29 [7]
2hrs, 142miles
42x+58=55x+32
13x=26
x=2hrs <---- answer
42*2+58=142
55*2+32=142mi <----answer
7 0
3 years ago
Read 2 more answers
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