Let A be the angle of 79 degrees
B be the angle of (5y-4) degrees
C be the angle of (x+5) degrees
D be the angle of (9z-7) degrees
According to the property of parallelogram
Opposite angles are equal
We get, angle A = angle C
Since angle A = 79 degrees
And angle C = (x+5) degrees
We get, x+5=79
=> x=79-5=74.
Angle B = Angle D
(5y-4)=(9z-7)
Since there’s two variables here, we can’t use the property of “opposite angles are equivalent”
We have to use another property which is adjacent angles are equal
Therefore, we can find angle D
Angle D + Angle A=180
=> 9z-7 =180-79
z=108/9
z=12
Since (5y-4)=(9z-7)
Substitute z=12 in
We get, 5y-4=101
y= 105/5
y= 21
Therefore, x=74, y=21 and z=12.
120÷100= 1.2
24÷1.2= 20
24 is 120% of 20
Answer:
TRUE
Step-by-step explanation:
We are given 2 triangles, ∆ABC and ∆DEF.
For the two trinagles to be considered similar, both must have their set of corresponding angles congruent to each other. That is, their corresponding angles are equal.
From the information given, the following are the set of corresponding angles:
<B = <E = 31°
<B = <D = 90°
<C = <F = 59° [180 - (90+31)]
The corresponding angles of both triangles are congruent. Therefore, it is guaranteed that ∆ABC is similar to ∆DEF (∆ABC ~ DEF).
when you add two negatives its just like regular number, -3+-5=-8 same as 3+5=8
